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3 years ago

Net force causes motion

Physics

2 answers:

ASHA 777 [7]3 years ago

8 0

Answer:

yes

Explanation:

IgorC [24]3 years ago

5 0

If an object has a net force acting on it, it will accelerate. The object will speed up, slow down or change direction. An unbalanced force (net force) acting on an object changes its speed and/or direction of motion.

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¿De qué altura cae un cuerpo que tarda 4 s en llegar al suelo? usar g = 10 m/s2 *

jasenka [17]

Answer:

Explanation:

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3 years ago

Group of physics students are asked to demonstrate Ohm’s Law in parallel circuits. Using their knowledge of Ohm’s Law and the r

astra-53 [7]

The student’s suggestion who provides enough evidence to be able to determine the value of each resistor is student D.

<h3>What is current?</h3>

The current is the stream of charges which flow inside the conductors when connected across the end of voltage.

For the given set of parallel resistors, we need to find the resistance of each resistor.

From the Ohm's law, V =IR

R = V/I

Resistance value depends upon the voltage difference across the resistor and the current flowing through that resistance.

Thus, the student D gives enough evidence to find resistance of the circuit is

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2 years ago

A baseball, which has a mass of 0.685 kg., is moving with a velocity of 38.0 m/s when it contacts the baseball bat duringwhich t

Evgen [1.6K]

Answers:

a) $65.075 kgm/s$

b) $10.526 s$

c) $61.82 N$

Explanation:

<h3>a) Impulse delivered to the ball</h3>

According to the Impulse-Momentum theorem we have the following:

$I=\Delta p=p_{2}-p_{1}$ (1)

Where:

$I$ is the impulse

$\Delta p$ is the change in momentum

$p_{2}=mV_{2}$ is the final momentum of the ball with mass $m=0.685 kg$ and final velocity (to the right) $V_{2}=57 m/s$

$p_{1}=mV_{1}$ is the initial momentum of the ball with initial velocity (to the left) $V_{1}=-38 m/s$

So:

$I=\Delta p=mV_{2}-mV_{1}$ (2)

$I=\Delta p=m(V_{2}-V_{1})$ (3)

$I=\Delta p=0.685 kg (57 m/s-(-38 m/s))$ (4)

$I=\Delta p=65.075 kg m/s$ (5)

This time can be calculated by the following equations, taking into account the ball undergoes a maximum compression of approximately $1.0 cm=0.01 m$ :

$V_{2}=V_{1}+at$ (6)

$V_{2}^{2}=V_{1}^{2}+2ad$ (7)

Where:

$a$ is the acceleration

$d=0.01 m$ is the length the ball was compressed

$t$ is the time

Finding $a$ from (7):

$a=\frac{V_{2}^{2}-V_{1}^{2}}{2d}$ (8)

$a=\frac{(57 m/s)^{2}-(-38 m/s)^{2}}{2(0.01 m)}$ (9)

$a=90.25 m/s^{2}$ (10)

Substituting (10) in (6):

$57 m/s=-38 m/s+(90.25 m/s^{2})t$ (11)

Finding $t$ :

$t=1.052 s$ (12)

<h3>c) Force applied to the ball by the bat </h3>

According to Newton's second law of motion, the force $F$ is proportional to the variation of momentum $\Delta p$ in time $\Delta t$ :

$F=\frac{\Delta p}{\Delta t}$ (13)

$F=\frac{65.075 kgm/s}{1.052 s}$ (14)

Finally:

$F=61.82 N$

6 0

3 years ago

Read 2 more answers

Where did we use rotational and irrotational flow

WARRIOR [948]

Answer:

The term rotational and irrotational flow is associated withe the flow of particles in fluid.

The common example of irrrotational flow can be seen on the carriages of the Ferris wheel (giant wheel).

Explanation:

If the fluid is rotating along its axis with the streamline flow of its particles,then this type of flow is rotational flow.
Similarly if fluid particles do not rotate along its axis while flowing in a stream line flow then it is considered as the irrotational flow.
In majority, if the flow of fluid is viscid then it is rotational.
Fluid in a rotating cylinder is an example of rotating flow.

3 0

3 years ago

The graph shows the displacement of a mouse

hram777 [196]

The farthest position the mouse reaches inside the tunnel is 4 meters into the tunnel.

From the graph,

The positions reached after,

5 s = 4 m

10 s = 2 m

20 s = 2 m

35 s = 3 m

40 s = 0 m

So the farthest position here is 4 m into the tunnel.

The rate of change of positions is displacement. So displacement will be change in initial and final positions divided by change in time.

s = Δx / Δt

Therefore, the farthest position the mouse reaches inside the tunnel is 4 meters into the tunnel.

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5 0

1 year ago