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Answer:
2.19 N/m
Explanation:
A damped harmonic oscillator is formed by a mass in the spring, and it does a harmonic simple movement. The period of it is the time that it does one cycle, and it can be calculated by:
T = 2π√(m/K)
Where T is the period, m is the mass (in kg), and K is the damping constant. So:
2.4 = 2π√(0.320/K)
√(0.320/K) = 2.4/2π
√(0.320/K) = 0.38197
(√(0.320/K))² = (0.38197)²
0.320/K = 0.1459
K = 2.19 N/m
Answer:
10.21 N
Explanation:
As the force is a vector, it can be decomposed in two components perpendicular each other, so there is no projection of one component in the direction of the other.
When divided in this way, the magnitude of the resultant vector can be found simply applying trigonometry, as follows:
F² = Fx² + Fy² ⇒ F = √(Fx)²+(Fy)²
Replacing by Fx= 5.17 N and Fy = 8.8 N, we get:
F = √(5.17)²+(8.8)² =10.21 N
Answer:
10.09 N
Explanation:
Analogously to Newton's second law, torque can be defined as:
![\tau=I\alpha](https://tex.z-dn.net/?f=%5Ctau%3DI%5Calpha)
Here, I is the moment of inertia and
is the angular acceleration. We have:
![\tau=(0.65kg*m^2)(29.5\frac{rad}{s^2})\\\tau=19.18N*m](https://tex.z-dn.net/?f=%5Ctau%3D%280.65kg%2Am%5E2%29%2829.5%5Cfrac%7Brad%7D%7Bs%5E2%7D%29%5C%5C%5Ctau%3D19.18N%2Am)
Torque is the vector product of the position vector of the point at which the force is applied by the force vector:
![\vec{\tau}=\vec{r}\times \vec{F}](https://tex.z-dn.net/?f=%5Cvec%7B%5Ctau%7D%3D%5Cvec%7Br%7D%5Ctimes%20%5Cvec%7BF%7D)
Since the effective lever arm is perpendicular to the force, the angle between them is
. The magnitud of this vector product is defined as:
.
Solving for F and replacing the known values:
![F=\frac{\tau}{rsen\theta}\\F=\frac{19.18N*m}{1.9m(sen90^\circ)}\\F=10.09N](https://tex.z-dn.net/?f=F%3D%5Cfrac%7B%5Ctau%7D%7Brsen%5Ctheta%7D%5C%5CF%3D%5Cfrac%7B19.18N%2Am%7D%7B1.9m%28sen90%5E%5Ccirc%29%7D%5C%5CF%3D10.09N)