Answer:
The force of friction acting on block B is approximately 26.7N. Note: this result does not match any value from your multiple choice list. Please see comment at the end of this answer.
Explanation:
The acting force F=75N pushes block A into acceleration to the left. Through a kinetic friction force, block B also accelerates to the left, however, the maximum of the friction force (which is unknown) makes block B accelerate by 0.5 m/s^2 slower than the block A, hence appearing it to accelerate with 0.5 m/s^2 to the right relative to the block A.
To solve this problem, start with setting up the net force equations for both block A and B:
where forces acting to the left are positive and those acting to the right are negative. The friction force F_fr in the first equation is due to A acting on B and in the second equation due to B acting on A. They are opposite in direction but have the same magnitude (Newton's third law). We also know that B accelerates 0.5 slower than A:
Now we can solve the system of 3 equations for a_A, a_B and finally for F_fr:
The force of friction acting on block B is approximately 26.7N.
This answer has been verified by multiple people and is correct for the provided values in your question. I recommend double-checking the text of your question for any typos and letting us know in the comments section.
Answer:
option B is the correct answer
Explanation:
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<span>coefficient
Let's look at the 3 possibilities and see what they are for </span>3H₂O₂ coefficient - This is used to indicate that multiple molecules are used for the formula. In 3H₂O₂ that indicates that we are talking about 3 molecules of H₂O₂ subscript - This is a small number set in a smaller font and placed low to the elements. It indicates the number of each type of atom in the compound. For the formula 3H₂O₂ there are 2 subscripts. Both of them being the number "2" set small and low just after the letters H and O. Those subscripts indicate that there are 2 hydrogen and 2 oxygen atoms per molecule.
element - This is the abbreviation for the elements used in the compound. In <span>3H₂O₂</span> there are 2 different elements. H to indicate hydrogen, and O to indicate oxygen.
Answer:
The motion is over-damped when λ^2 - w^2 > 0 or when 
> 0.86
The motion is critically when λ^2 - w^2 = 0 or when = 0.86
The motion is under-damped when λ^2 - w^2 < 0 or when < 0.86
Explanation:
Using the newton second law
k is the spring constante
b positive damping constant
m mass attached
x(t) is the displacement from the equilibrium position
Converting units of weights in units of mass (equation of motion)
From hook's law we can calculate the spring constant k
If we put m and k into the DE, we get
Denoting the constants
2λ = 
= 
λ = b/0.215
λ^2 - w^2 = 
This way,
The motion is over-damped when λ^2 - w^2 > 0 or when > 0.86
The motion is critically when λ^2 - w^2 = 0 or when = 0.86
The motion is under-damped when λ^2 - w^2 < 0 or when < 0.86
