If 03.4 kg of water at 69°C is changed into steam at 100°C, how will the energy be used? specific heat capacity of water is 4200
1 answer:
You might be interested in
Answer:
a) Initial Value Problem
dv/dt = 4 - 0.1v
v(0) = 0
b) solution to the IVP
v(t) = 40(1 - e^(-t/10))
c) Limiting velocity
Vo = 40 ft/s
Position of the car after 12 hours
X = 14,390 ft
Explanations:
The complete explanations of each of the sections contained in the question are in the files attached to this solution.
Answer:
x=0.01457 m
Explanation:
From parallel axis theorem
I=Icm+mh²
where h=x
The rotational inertia about its center of mass is
Icm=mL²/12
where L=1.0 m
Thus T=4.8s we obtain
After Solving this quadratic we get
x₁=5.702 m
x₂=0.01457 m
One of the solution is an impossible value for x (x=5.70m is greater than L)
So we choose the other one
x=0.01457 m