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ivanzaharov [21]
3 years ago
15

PLS HELP! WILL MARK BRAINLIEST!!! 50 PTS

Chemistry
1 answer:
AveGali [126]3 years ago
3 0

Answer:

from the pic:

empirical \: formular :  \:  \: C  _{2}H _{3}O _{2}

since molar mass is 118.084 g/mol;

(C  _{2}H _{3}O _{2}) _{n} = 118.084 \\ C  _{2n}H _{3n}O _{2n} = 118.084 \\(12 \times 2)  _{n} + (1 \times 3) _{n} + (16 \times2 ) _{n} = 118.084 \\ 24_{n} + 3_{n} + 32_{n} = 118.084 \\ 59_{n} = 118.084 \\ n = 2

{ \boxed{ \bf{molecular \: formular :  \: C  _{4}H _{6}O _{4}}}}

It is an aldehyde with structure ( second pic )

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8 0
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Suppose a 10.0 mL sample of an unknown
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The concentration of HCl is equal to 2.54mol/L.

<h3>Mole calculation</h3>

To solve this question, one must use the molarity calculation, which corresponds to the following expression:

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Thus, to find the molarity of the sample, the following calculations must be performed:

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So, 0.00254 moles were added per 10ml, so we can do:

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So, the concentration of HCl is equal to 2.54mol/L.

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6 0
2 years ago
The mass of Carbon is 12 g/mol and the mass of oxygen is 16 g/mol. What is the approximate percent composition by mass of CO2 (f
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5 0
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