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3 years ago

PLS HELP! WILL MARK BRAINLIEST!!! 50 PTS

Chemistry

1 answer:

AveGali [126]3 years ago

3 0

Answer:

from the pic:

$empirical \: formular : \: \: C _{2}H _{3}O _{2}$

since molar mass is 118.084 g/mol;

$(C _{2}H _{3}O _{2}) _{n} = 118.084 \\ C _{2n}H _{3n}O _{2n} = 118.084 \\(12 \times 2) _{n} + (1 \times 3) _{n} + (16 \times2 ) _{n} = 118.084 \\ 24_{n} + 3_{n} + 32_{n} = 118.084 \\ 59_{n} = 118.084 \\ n = 2$

${ \boxed{ \bf{molecular \: formular : \: C _{4}H _{6}O _{4}}}}$

It is an aldehyde with structure ( second pic )

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wariber [46]

Mass of aluminum = (1.50 m^3)( 2.70 x 10^3 kg/m^3) = 4050 kg

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brainly.com/question/246454

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7 0

2 years ago

If 0.35 moles of kcl was dissolved in enough water to make 0.2 L of solution, what is molarity?

Mars2501 [29]

Answer:

1.75M

Explanation:

molarity = number of moles of solute/ number of L of solution =

=0.35 mol/0.2L = 1.75 mol/L = 1.75 M

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3 years ago

A different student is given a 10.0g sample labeled CaBr2 that may contain an inert (nonreacting) impurity. Identify a quantity

grandymaker [24]

Answer:

Mass of Ca in sample, Mass of Br in sample, Number of moles of Ca in sample, Number of moles of Br in sample, Mass or moles of element other than Ca or Br in sample

Explanation:

The AP Classroom will not count your answer to this question as correct unless it includes at least one of the answers listed above. If you say that theanswer to this question is density, it will be marked as incorrect, I found that out the hard way when I used the answers that brainly gave me.

Good luck,

I applaud you for using the sources avalible to you, which is /definetly not/ cheeting.

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3 years ago

A 48.0g sample of quartz, which has a specific heat capacity of 0.730·J·g−1°C−1, is dropped into an insulated container containi

Butoxors [25]

Answer:

The equilibrium temperature of the water is 26.7 °C

Explanation:

<u>Step 1:</u> Data given

Mass of the sample quartz = 48.0 grams

Specific heat capacity of the sample = 0.730 J/g°C

Initial temperature of the sample = 88.6°C

Mass of the water = 300.0 grams

Initial temperature = 25.0°C

Specific heat capacity of water = 4.184 J/g°C

<u>Step 2:</u> Calculate final temperature

Qlost = -Qgained

Qquartz = - Qwater

Q =m*c*ΔT

Q = m(quartz)*c(quartz)*ΔT(quartz) = -m(water) * c(water) * ΔT(water)

⇒ mass of the quartz = 48.0 grams

⇒ c(quartz) = the specific heat capacity of quartz = 0.730 J/g°C

⇒ ΔT(quartz) = The change of temperature of the sample = T2 -88.6 °C

⇒ mass of water = 300.0 grams

⇒c(water) = the specific heat capacity of water = 4.184 J/g°C

⇒ ΔT= (water) = the change in temperature of water = T2 - 25.0°C

48.0 * 0.730 * (T2-88.6) -300.0 * 4.184 *(T2 - 25.0)

35.04(T2-88.6) = -1255.2 (T2-25)

35.04T2 -3104.544 = -1255.2T2 + 31380

1290.24T2 = 34484.544

T2 = 26.7 °C

The equilibrium temperature of the water is 26.7 °C

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3 years ago

I'll give brainless! no l!nks!!!

Nastasia [14]

Answer:

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2 years ago