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Serga [27]
3 years ago
8

Does a precipitate form when a solution of sodium acetate and a solution of ammonium sulfate are mixed together?

Chemistry
1 answer:
e-lub [12.9K]3 years ago
5 0
<h3><u>Answer</u>;</h3>

No, a precipitate does not form

<h3><u>Explanation</u>;</h3>
  • Precipitation involves mixing or combining solutions that contain soluble ionic compounds to form an insoluble ionic compound by a reaction.
  • Sodium acetate and ammonium sulfate are both soluble ionic compounds, which implies that they exist as ions in aqueous solution.
  • <em><u>When they combine they form NH4CH3COOH and sodium sulfate, Na2SO4, which are both soluble salts, as all salts of ammonium and sodium are soluble.</u></em>
  • <em><u>Both ammonium acetate and sodium sulfate are soluble because there are no anions that can form an insoluble solid with NH4+ and Na+ cations. </u></em>
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A 12 gram piece of Cu at 475 oC is placed in contact with a 15 gram piece of Cr at 265 oC.
ale4655 [162]

Answer:

349.22°C

Explanation:

Let the final temperature of the two pieces of metal be x.

Now, the warmer metal which is C u reduces from 475°C to x. Thus Δt for C u is; Δt1 = 475 - x.

The cooler metal Cr increases in temperature from 265°C to x. Thus, it's change in temperature is Δt for Cr is; Δt2 = x - 265.

Now from conservation of energy, the amount of energy leaving the C u metal is equal to the amount of energy entering the Cr metal.

Thus;

q_lost = q_gain

Where;

q_lost = m1•c1•Δt1

q_gained = m2•c2•Δt2

Now, c1 & c2 are the specific heat capacity of C u and Cr respectively.

From online tables, c1 = 0.385 J/g°C and c2 = 0.46 J/g°C

We are given;

m1 = 12g and m2 = 15g

Thus;

12 × 0.385 × (475 - x) = 15 × 0.46 × (x - 265)

2194.5 - 4.62x = 6.9x - 1828.5

6.9x + 4.62x = 2194.5 + 1828.5

11.52x = 4023

x = 4023/11.52

x = 349.22°C

4 0
3 years ago
Assuming complete distribution, what is the molarity of 10 milligrams of lisinopril in 100 liters?
SVEN [57.7K]

Answer:

2.47x10^{-7}   M

Explanation:

Lisoprisil's molecular mass is 405.488g/mol, we'll use this fact to calculate molarity, which units are mol/L, and we proceed to the calculus:

  • First, we'll unify unities, the 10 milligrams of lisinopril we'll transform into grams.

10mg*\frac{1g}{1000mg}=0.01g

  • Now that we have the same unities we'll calculate molarity using the molecular mass, the grams of lisinopril and the liters in which these grams are, let's consider that our final unities have to be mol/L.

\frac{1mol}{405.488g}*\frac{0.01g}{100L}=2.47x10^{-7}   M

I hope you find this information useful and interesting! Good luck!

3 0
3 years ago
Is soil a producer, decomposer, or consumer
barxatty [35]

Plants are the producers — they use the sun's energy to convert water and carbon dioxide into plant material via photosynthesis. ... A producer is a living thing that makes its own food from sunlight, air, and soil. Green plants are producers who make food in their leaves.
6 0
2 years ago
Read 2 more answers
A gas bottle contains 8. 61×1023 oxygen molecules at a temperature of 359. 0 k. what is the thermal energy of the gas? (you migh
Cloud [144]

A gas bottle contains 8. 61×1023 oxygen molecules at a temperature of 359. 0 k then the thermal energy of the gas is 6.35KJ.

<h3>What is thermal energy? </h3>

Thermal energy is the energy contained within a system which is responsible for its temperature. Heat is also termed as flow of thermal energy.

Thermal energy is directly proportional to the temperature. As temperature increase thermal energy increases.

Given,

temperature = 395K

Number of oxygen molecules= 8.61 × 10^(23)

Firstly we will calculate the number of moles = N/A

where A is the avagadro number = 6.022 × 10^(23)

number of moles = 8.61 × 10^(23)/6.022 ×10^(23)

number of moles = 1.42moles

Using the energy equation,

E = 3/2 × nRT

where R is the gas constant = 8.314J/molK

E = 3/2 × 1.42 × 8.314 × 359

= 6357.4J

= 6.35KJ

Thus, we found that the thermal energy of the gas is 6.35KJ.

learn more about thermal energy:

brainly.com/question/2409175

#SPJ4

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1 year ago
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