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LenKa [72]
2 years ago
12

Determine the molarity of 1.2 mol KCl in 1.1 L of a solution?

Chemistry
1 answer:
victus00 [196]2 years ago
7 0

Answer:

1.1 M

General Formulas and Concepts:

  • Molarity = moles of solute / liters of solution

Explanation:

<u>Step 1: Define variables</u>

1.2 mol KCL

1.1 L of solution

M = unknown

<u>Step 2: Solve for Molarity</u>

  1. Substitute:                    M = 1.2 mol/1.1 L
  2. Evaluate:                       M = 1.09091

<u>Step 3: Check</u>

<em>We are given 2 sig figs. Follow sig fig rules.</em>

1.09091 M ≈ 1.1 M

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Given that the initial rate constant is 0.0110s−1 at an initial temperature of 21 ∘C , what would the rate constant be at a temp
gulaghasi [49]

The rate constant is mathematically given as

K2=2.67sec^{-1}

<h3>What is the Arrhenius equation?</h3>

The rate constant for a particular reaction may be calculated with the use of the Arrhenius equation. This constant can be stated in terms of two distinct temperatures, T1 and T2, as follows:

ln(\frac{K2}{K1})= (\frac{Ea}{R})*(\frac{1}{T1}-\frac{1}{T2})

Therefore

KT1= 0.0110^{-1}

T1= 21+273.15

T1= 294.15K

T2= 200  

T2=200+273.15

T2= 473.15K

Ea= 35.5 Kj/Mol

Hence, in  j/mol R Ea is

Ea=35.5*1000 j/mol R

ln(\frac{K2}{0.0110})= (\frac{35.5*1000}{8.314})*(\frac{1}{294.15}-\frac{1}{473.15}\\\\ln(\frac{K2}{0.0110})=5.492

K2/0.0110 =e^(5.492)

K2/0.0110 =242.74

K2= 242.74*0.0110

K2=2.67sec^{-1}

In conclusion, rate constant

K2=2.67sec^{-1}

Read more about rate constant

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5 0
1 year ago
A 5 g sample of pure gold has a density of 19.3 g/ml. Your friend purchased a gold ring that was made of 25 g of pure gold. What
patriot [66]

Answer:

96.5 g/ml

Explanation:

If 5g is 19.3 then 25g is 19.3x5 which is 96.5 g/ml

7 0
2 years ago
Read 2 more answers
5. Element X has two isotopes: X-100 and X-104. If the atomic mass of X is 101
Alex

Answer:

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5 0
2 years ago
What is the pH of a substance with a hydrogen concentration of 1.0 x 10-13?
Nikolay [14]

Answer:

Favorite Answer

1.0 x10^-14 = (1.0 x 10^-13) (x)

x = 1.0 x 10^-1 = 0.1 M (this is the [OH-])

pOH = -log 0.1 = 1.0

Explanation:

I hope this helps :) sorry if not :(

4 0
3 years ago
How many atoms are in 8.28 moles of aluminum?
Lilit [14]

Answer:

49.86 × 10²³  atoms of Al

Explanation:

Given data:

Number of moles of Al = 8.28 mol

Number of atoms = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

For 8.28 moles of Al:

1 mole = 6.022 × 10²³  atoms of Al

8.28 mol×6.022 × 10²³  atoms / 1mol

49.86 × 10²³  atoms of Al

4 0
3 years ago
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