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VashaNatasha [74]
3 years ago
9

A(n) BLANK authenticates various specimens in a collection for a museum.

Engineering
1 answer:
mezya [45]3 years ago
4 0

Answer:

Curators

Explanation:

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Can someone please answer this, it will be very appreciative
Lisa [10]

Answer:

sorry the image isn't clear

Explanation:

7 0
2 years ago
Lawn maintenance is an alternative energy source<br> -true<br> -false
Reika [66]

Answer:

false

Explanation:

4 0
3 years ago
The steady-state data listed below are claimed for a power cycle operating between hot and cold reservoirs at 1200 K and 400 K,
lesya692 [45]

Answer:

a. Irreversible

b. Impossible

c. Impossible

Explanation:

to determine if a case is reversible, irreversible or impossible we compare the actual efficiency to the maximum efficiency of each case

maximum efficiency of the power cycle

nmax = 1 - TC/TH

nmax = 1 - 400/1200

Check attachment for complete solution

8 0
3 years ago
Read 2 more answers
Sea water with a density of 1025 kg/m3 flows steadily through a pump at 0.21 m3 /s. The pump inlet is 0.25 m in diameter. At the
myrzilka [38]

Answer:

\dot W_{pump} = 16264.922\,W\,(16.265\,kW)

Explanation:

The pump is modelled after applying Principle of Energy Conservation, whose form is:

\frac{P_{1}}{\rho\cdot g}+ \frac{v_{1}^{2}}{2\cdot g} +z_{1} + h_{pump}=\frac{P_{2}}{\rho\cdot g}+ \frac{v_{2}^{2}}{2\cdot g} +z_{2}

The head associated with the pump is cleared:

h_{pump} = \frac{P_{2}-P_{1}}{\rho\cdot g}+\frac{v_{2}^{2}-v_{1}^{2}}{2\cdot g}+(z_{2}-z_{1})

Inlet and outlet velocities are found:

v_{1} = \frac{0.21\,\frac{m^{3}}{s} }{\frac{\pi}{4}\cdot (0.25\,m)^{2} }

v_{1} \approx 4.278\,\frac{m}{s}

v_{2} = \frac{0.21\,\frac{m^{3}}{s} }{\frac{\pi}{4}\cdot (0.152\,m)^{2} }

v_{2} \approx 11.573\,\frac{m}{s}

Now, the head associated with the pump is finally computed:

h_{pump} = \frac{175\,kPa-81.326\,kPa}{(1025\,\frac{kg}{m^{3}} )\cdot (9.807\,\frac{m}{s^{2}} )} +\frac{(11.573\,\frac{m}{s} )^{2}-(4.278\,\frac{m}{s} )^{2}}{2\cdot (9.807\,\frac{m}{s^{2}} )} + 1.8\,m

h_{pump} = 7.705\,m

The power that pump adds to the fluid is:

\dot W_{pump} = \dot V \cdot \rho \cdot g \cdot h_{pump}

\dot W_{pump} = (0.21\,m^{3})\cdot (1025\,\frac{kg}{m^{3}})\cdot (9.807\,\frac{m}{s^{2}})\cdot(7.705\,m)

\dot W_{pump} = 16264.922\,W\,(16.265\,kW)

4 0
3 years ago
A train travels 650 meters in 25 seconds. What is the train's velocity?
frosja888 [35]

The train is traveling 26 meters A second .

3 0
3 years ago
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