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2 years ago

14

A(n) _____ is an apparatus that changes alternating current (AC) to direct current (DC)

1 answer:

amid [387]2 years ago

7 0

Answer:

rectifier

Explanation:

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Fresh ideas or title to be researched for civil engineering individual final project for diploma students also can extend the to

Mekhanik [1.2K]

Answer:

What type of projects do civil engineers work on?

Civil engineers design major transportation projects. Civil engineers conceive, design, build, supervise, operate, construct and maintain infrastructure projects and systems in the public and private sector, including roads, buildings, airports, tunnels, dams, bridges, and systems for water supply and sewage treatment

Explanation:

8 0

2 years ago

How many points do you need to define for the rectangle

Rudik [331]

Answer:

Two points

Explanation:

3 0

3 years ago

The diffusion coefficients for iron in nickel are given at two temperatures:T (K)D (m2/s)12739.4 × 10–1614732.4 × 10–14(a) Deter

hram777 [196]

Answer:

The diffusion coefficients for iron in nickel are given at two temperatures:

T (K) 1273 1473

D ( $m^{2}$ /s) 9.4 × $10^{-16}$ 2.4 × $10^{-14}$

(a) Determine the values of Do and the activation energy Qd.

(b) What is the magnitude of D at 1100°C (1373 K)?

<em>A </em>

<em>The pre-exponential factor Do = 2.1 x </em> $10^{-16}$ <em></em>

<em>The activation energy Qd = 252,609 J/mol</em>

<em>B</em>

<em>The diffusion coefficient D= 5.14 x </em> $10^{-15}$ <em></em>

Explanation:

The full explanation is contained in the attached images;

5 0

4 years ago

2. Other igneous rock forms from lava that cools quickly on Earth’s surface. Classify the rock as either intrusive or extrusive,

Darya [45]

Answer:

extrusive,

Explanation:

lava exlodes outwards, making it extrusive and not intrusive.

5 0

3 years ago

An Ideal gas is being heated in a circular duct as while flowing over an electric heater of 130 kW. The diameter of duct is 500

Assoli18 [71]

Answer: The exit temperature of the gas in deg C is $32^{o}C$ .

Explanation:

The given data is as follows.

$C_{p}$ = 1000 J/kg K, R = 500 J/kg K = 0.5 kJ/kg K (as 1 kJ = 1000 J)

$P_{1}$ = 100 kPa, $V_{1} = 15 m^{3}/s$

$T_{1} = 27^{o}C = (27 + 273) K = 300 K$

We know that for an ideal gas the mass flow rate will be calculated as follows.

$P_{1}V_{1} = mRT_{1}$

or, m = $\frac{P_{1}V_{1}}{RT_{1}}$

= $\frac{100 \times 15}{0.5 \times 300}$

= 10 kg/s

Now, according to the steady flow energy equation:

$mh_{1} + Q = mh_{2} + W$

$h_{1} + \frac{Q}{m} = h_{2} + \frac{W}{m}$

$C_{p}T_{1} - \frac{80}{10} = C_{p}T_{2} - \frac{130}{10}$

$(T_{2} - T_{1})C_{p} = \frac{130 - 80}{10}$

$(T_{2} - T_{1})$ = 5 K

$T_{2}$ = 5 K + 300 K

$T_{2}$ = 305 K

= (305 K - 273 K)

= $32^{o}C$

Therefore, we can conclude that the exit temperature of the gas in deg C is $32^{o}C$ .

8 0

4 years ago