<u>Answer:</u><u> </u><u>3</u><u>4</u><u> </u><u>m</u><u>o</u><u>r</u><u>e</u><u> </u><u>p</u><u>o</u><u>u</u><u>c</u><u>h</u><u>e</u><u>s</u>
7 boxes - fish food; 1 box contained 6 pouches
Total amount of fish food is 7 × 6 = 42 pouches of fish food
2 packets - cat food; 1 packet contained 4 pouches
Total amount of cat food is 2 × 4 = 8 pouches
How many more pouches of fish food than cat food did Shelly buy?
42 pouches - 8 pouches = 34 pouches
Therefore there was 34 more pouches of fish food than cat food
Answer:
1. Range is 37,IQR is 16.5, MAD is 9
2.Range is 35,IQR is 14, MAD is 8
3. Range is 76,IQR is 37, MAD is 19.1
4. Range is 8, IQR is 4, Mad is 20.4
5. Range is 62,IQR is16 , MAD is 13.08
6. Range is 42,IQR is 23,MAD is 12
Step-by-step explanation:
mrk me brainliest plz
Answer:12533
Step-by-step explanation:
Answer:
24 hours
Step-by-step explanation:
One member of the gardening club can alone plant flowers in 12 hours.
So in 1 hour he can plant 1/12 of the flowers.
Let the time required by the second member of the club to plant flowers alone be x hours.
Then in 1 hour he can plant 1/x of the flowers.
Now when the two members work together,each hour they can plant:
of the flowers.
But they can together complete the job in 8 hours. So in one hour they plant 1/8 of the flowers.
=> ![\[\frac{1}{12}+\frac{1}{x}=\frac{1}{8}\]](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7B1%7D%7B12%7D%2B%5Cfrac%7B1%7D%7Bx%7D%3D%5Cfrac%7B1%7D%7B8%7D%5C%5D)
=> ![\[\frac{1}{x}=\frac{1}{24}\] ](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7B1%7D%7Bx%7D%3D%5Cfrac%7B1%7D%7B24%7D%5C%5D%0A)
=> x=24
So the second member can plant the flowers alone in 24 hours
Here we might have to find p(v intersection w) and for that we use the following formula
p(v U w) = p(v)+p(w)-p(v intersection w)
And it is given that p(v) =01.3 , p(w) = 0.04 and p(v U w ) = 0.14 .
Substituting these values in the formula, we will get
0.14 = 0.13 +0.04 -p(v intersection w)
p(v intersection w) =0.13 +0.04 -0.14 = 0.03
So the required answer of the given question is 0.03 .