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Marysya12 [62]
3 years ago
8

The type of heat transfer responsible for distributing most of the heat throughout Earth's atmosphere is

Chemistry
2 answers:
Marta_Voda [28]3 years ago
8 0

<em>A</em><em>.</em><em> </em>

Explanation:

<em>hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em><em> </em><em>if</em><em> </em><em>im</em><em> </em><em>incorrect</em><em>.</em><em> </em><em>please</em><em> </em><em>report</em><em> </em><em>so</em><em> </em><em>people</em><em> </em><em>don't</em><em> </em><em>think</em><em> </em><em>its</em><em> </em><em>the</em><em> </em><em>correct</em><em> </em><em>answer</em><em>.</em><em> </em><em><</em><em>3</em>

geniusboy [140]3 years ago
3 0

Answer:

A

Explanation:

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How many moles of chromium III nitrate are produced When chromium reacts with 0.85 moles of lead for nitrate to produce chromium
Pepsi [2]

0.85 moles formula units of lead nitrate will produce 0.57 moles formula units of chromium (III) nitrate.

<h3>Explanation</h3>

Typically, the oxidation state of Pb in lead nitrate tend to be +2. In other words, Pb in lead nitrate tends to exist as \text{Pb}^{2+} ions. The formula for a nitrate ion is {\text{NO}_3}^{-}. The charge on each of the nitrate ion is -1. The charge on the two ions should balance. As a result, each \text{Pb}^{2+} ion in lead nitrate would pair up with two {\text{NO}_3}^{-} ions. The formula for lead nitrate will be \text{Pb}({\text{NO}_3})_2. Each formula unit of lead nitrate will contain one \text{Pb}^{2+} ion and two {\text{NO}_3}^{-} ions.

The "III" in the name "chromium (III) nitrate" is a Roman Numeral. It indicates that the oxidation state of Cr in chromium (III) nitrate is +3. The Cr in that compound will exist as \text{Cr}^{3+}. Similarly, each \text{Cr}^{3+} will pair up with three {\text{NO}_3}^{-} ions. The formula for chromium (III) nitrate will be \text{Cr}(\text{NO}_3})_3. Each formula unit of chromium (III) nitrate will contain one {\text{NO}_3}^{-} ion and three {\text{NO}_3}^{-} ions.

0.85 moles formula units of lead nitrate will contain 0.85 × 2 = 1.7 moles of {\text{NO}_3}^{-} ions. Those nitrate ions will end up in 1.7 / 3 = 0.57 moles formula units of chromium (III) nitrate. As a result, the reaction will produce 0.57 moles formula units of chromium (III) nitrate.

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1 atom Mg, 2 atoms O and 2 atoms H.

1 + 2 + 2 = 5, so correct answer is C

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