Answer:
28Nm
Explanation:
Torque is expressed as the prduct of force and radius
Given
Force = 140N
radius = 0.20m
Torque = 140 * 0.2
Torque = 140 * 1/5
Torque = 28Nm
Hence the amouunt of torque applied is 28Nm
The given question is incomplete. The complete question is as follows.
Boxes A and B in the figure have masses of 13.4 kg. and 4.8 kg. , respectively. The two boxes are released from rest. What would be the speed of the boxes when box b has fallen a distance of 0.50 m? The coefficient of kinetic friction between box a and the surface it slides on is 0.20. Use conservation of energy.
Explanation:
Let us assume that box B is falling down, so equation of force for box B is as follows.
T =
.......... (1)
Now, force of equation for box A is as follows.


T =
........... (2)
We will equate both equation (1) and (2) as follows.
= 


a = 
= 1.1415 
Now, we will calculate the velocity of the box after falling through a distance of 0.50 m as follows.

= 
= 1.07 m/s
Thus, we can conclude that speed of the given boxes is 1.07 m/s.
it is basalt which is an igneous rock
Refer to the diagram shown.
F = 65 N, the force exerted by Dwight.
The horizontal component of the force is
65 cos(50°) = 41.8 N
The vertical component of the force is
65 sin(50°) = 49.8 N
Answer:
Horizontal: 41.8 N
Vertical: 49.8 N
Answer:
An unknown number of identical light bulbs are connected to a 15 V battery in parallel. The current through the battery is 2 A. If the light bulbs are connected to the battery in series, the current through the battery is 5 mA. How many bulbs are there?
3 bulbs are there from the analogy given above
Explanation: