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ankoles [38]
2 years ago
11

PLEASE HELP DUE TODAY!!

Physics
1 answer:
77julia77 [94]2 years ago
3 0

Answer:

1. −1.10400000*10^−17

2.5,750

3. 27 electrons = −4.32000000*10^−18

4. Don't remember how to do

5) Same, don't remember how to do

Explanation:

Hope this at least helped

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It is now virtually certain that the dominant cause of recent ice ages is
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<span>Variations in Earth-Sun orbital relationships.</span>
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The sun’s___and the planet’s___keeps planets moving is___orbits.
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The sun’s gravitational attraction and the planet’s inertia keeps planets moving is circular orbits.

Explanation:

The planets in the Solar System move around the Sun in a circular orbit. This motion can be explained as a combination of two effects:

1) The gravitational attraction of the Sun. The Sun exerts a force of gravitational attraction on every planet. This force is directed towards the Sun, and its magnitude is

F=G\frac{Mm}{r^2}

where

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2) The inertia of the planet. In fact, according to Newton's first law, an object in motion at constant velocity will continue moving at its velocity, unless acted upon an external unbalanced force. Therefore, the planet tends to continue its motion in a straight line (tangential to the circular orbit), however it turns in a circle due to the presence of the gravitational attraction of the Sun.

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8 0
3 years ago
What is the correct equation for calculating the average atomic mass for 3 isotopes? (pls be 100%of your answer pls no guessing)
mariarad [96]

<u>Answer:</u>

<em>The correct equation for measuring the average microscopic weight  for 3 isotopes is multiply the rate of abundance by each weight and add them.</em>

<u>Explanation:</u>

To calculate the average microscopic mass of element using weights and relative abundance we have to follow the following steps.

  • Take the correct weight of each isotope (that will be in decimal form)
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<em>This gives the required  average microscopic weight of the three isotopes.</em>

3 0
3 years ago
A wire is wrapped 200 times around a hollow cylinder of cross-sectional area 12 cm2 and length 10 cm. Assuming the turns are spr
Sonja [21]

Answer:

The answer is 10.857mJ

Explanation:

The energy stored in this solenoid is given by the below mentioned equation,

U = L*I^{2}/2

where L the inductance of this solenoid is given by the below mentioned equation,

L = u_{0} *N^{2}*A/L

Plugging this into the energy equation you obtain the equation for the total energy stored in the magnetic field of the solenoid, given by,

U = u_{0} *N^{2}*A*I^{2}/(2*L)

where u_{0} is the permeability of free space which equals to u_{0} = 4*\pi *10^{-7} T.m/A. Plugging all the quantities into the above equation from the data in the question after converting to standard units. of meters instead of centimeters, we get for the energy stored in the coil,

U = 10.857mJ

7 0
3 years ago
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