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mariarad [96]
3 years ago
5

1. Tooth enamel consists mainly of hydroxyapatite (Ca5(PO4)3(OH). When tin(II)fluoride is added to toothpaste it reacts with the

enamel to produce a more decay-resistant material fluoroapatite ( Ca5(PO4)3F. The by-products of this reaction are tin(II)oxide and water. What mass of hydroxyapatite can be converted to fluoroapatite by reaction with 0.115 grams of tin(II)fluoride
Chemistry
1 answer:
Sliva [168]3 years ago
3 0

<u>Answer:</u> The mass of hydroxyapatite that can be converted is 0.733 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

Given mass of tin(II)fluoride  = 0.115 g

Molar mass of tin(II)fluoride = 156.7 g/mol

Putting values in equation 1, we get:

\text{Moles of tin(II)fluoride}=\frac{0.115g}{156.7g/mol}=0.00073mol

The chemical equation for the reaction of tin(II)fluoride and hydroxyapatite follows:

SnF_2+2Ca_5(PO_4)_3(OH)\rightarrow 2Ca_5(PO_4)_3F+SnO+H_2O

By Stoichiometry of the reaction:

1 mole of tin (II) fluoride reacts with 2 moles of hydroxyapatite

So, 0.00073 moles of tin (II) fluoride will react with = \frac{2}{1}\times 0.00073=0.00146mol of hydroxyapatite

Now, calculating the mass of hydroxyapatite by using equation 1, we get:

Moles of hydroxyapatite = 0.00146 moles  

Molar mass of hydroxyapatite = 502.3 g/mol

Putting values in equation 1, we get:

0.00146mol=\frac{\text{Mass of hydroxyapatite}}{502.3g/mol}\\\\\text{Mass of hydroxyapatite}=(0.00146mol\times 502.3g/mol)=0.733g

Hence, the mass of hydroxyapatite that can be converted is 0.733 grams

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4 0
3 years ago
Before we can use this equation for
AlexFokin [52]

Answer:

2C₂H₆ +  [7]O₂     →      [4]CO₂ + [6]H₂O

Explanation:

Chemical equation:

C₂H₆ +  O₂     →      CO₂ + H₂O

Balanced chemical equation:

2C₂H₆ +  7O₂     →      4CO₂ + 6H₂O

Step 1:

2C₂H₆ +  O₂     →      CO₂ + H₂O

Left hand side                      Right hand side

C = 4                                     C = 1

H = 12                                    H = 2

O = 2                                     O = 3

Step 2:

2C₂H₆ +  O₂     →      4CO₂ + H₂O

Left hand side                      Right hand side

C = 4                                     C =  4

H = 12                                    H = 2

O = 2                                     O = 9

Step 3:

2C₂H₆ +  O₂     →      4CO₂ + 6H₂O

Left hand side                      Right hand side

C = 4                                     C =  4

H = 12                                    H = 12

O = 2                                     O = 14

Step 4:

2C₂H₆ +  7O₂     →      4CO₂ + 6H₂O

Left hand side                      Right hand side

C = 4                                     C =  4

H = 12                                    H = 12

O = 14                                     O = 14

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Explanation:

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In this case, according to the given information, it turns out possible for us to solve for the molarity of the KOH solution by knowing this base react in a 1:1 mole ratio with nitric acid, HNO3; thus, we can write the following equation, as their moles are the same at the endpoint:

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Regards!

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