Answer:
Given info : 500 cc of 2N Na2CO3 are mixed with 400 cc of 3N H2SO4 and volume was diluted to one litre. To find : will the resulting solution is acidic , basic or neutral ? Calculate the molarity of the dilute solution. solution : no of moles of Na2CO3 = normality/n %3D - factor x volume 2/2 x 500/1000 = 0.5 mol %D no of moles of H2SO4 = 3/2 x 400/100O = 0.6 mol %3D We see, Na2CO3 + H2S04 => Na2S04 + CO2 + H2O Here one mol of Na2C03 reacts with one mole of H2SO4. So, 0.5 mol of Na2CO3 reacts with 0.5 mol of H2SO4. so, remaining 0.1 mol of H2SO4 makes solution acidic. Now molarity of solution = remaining no of moles of H2SO4/volume of solution= 0.1/1 = %3D 0.1M
Answer:
Below 0° degrees Celcius
Explanation:
For deposition (gas to solid) to happen, the temperature has to be below 0° Celsius. If so, deposition occurs, and ice crystals form.
Answer:
ummmm... whats this supposed to mean? any answer choices
Explanation:
Answer:
CH2
Explanation:
We are given that a compound is 14.40% hydrogen and 85.60% carbon.
Let the mass of the substance be 100g.
Mass of the hydrogen: 14.40% of 100 = 14.40 g
Mass of the carbon: 85.60% of 100 = 85.60 g
Now, let's find the moles of hydrogen:
Moles of carbon:
Let's put these in a ratio and simplify:
7.13 mole C: 14.40 mole H
1 mole C: 2 mole H
Therefore, the empirical formula of this compound is CH2.
Hope this helps!! If you have any questions about my work, please let me know in the comments!
For the first one it is C the muscle system
For the second one it is A allow movement in the body
For the third one it is C Skeletal Muscles
