Q = mCpΔT —> Solve for Cp —> Cp = q/mΔT
q = -6700 J (negative because it released heat
m = 70 g
ΔT = Final temp - initial temp = 25 - 90 = -65°C
Cp = -6700 J / (70 g)(-65°C) = 1.47 J/g°C
Find the molar mass of Fe_2O_3
2Fe = 2*56 = 112
3O = 3* 16 = 48
Molar Mass = 160 grams
moles= given mass / molar mass
moles = 28 / 160
moles = 0.175 <<<< answer
Chemical science deals with mater like compound mater
Answer:
Empirical formula is C₃H₃O.
Explanation:
Given data:
Mass of compound = 0.519 g
Mass of CO₂ = 1.24 g
Mass of H₂O = 0.255 g
Empirical formula = ?
Solution:
%age of C,H,O
C = 1.24 g/0.519 × 12/44 ×100 = 65.5%
H = 0.255 g/0.519 × 2.016/18 ×100 = 5.6%
O = 100 - (65.5+5.6)
O = 28.9%
Number of gram atoms of H = 5.6 / 1.01 = 5.5
Number of gram atoms of O = 28.9 / 16 = 1.81
Number of gram atoms of C = 65.5 / 12 = 5.5
Atomic ratio:
C : H : O
5.5/1.81 : 5.5/1.81 : 1.81/1.81
3 : 3 : 1
C : H : O = 3 : 3 : 1
Empirical formula is C₃H₃O.
