Answer:
In brief, electrons in the K⁺ ion occupy three main electron shells. In comparison, electrons in the Na⁺ ion occupy only two main electron shells.
Explanation:
Consider the electron cloud model for the structure of an atom or an ion. The nucleus was very dense and small. It was highly located at the center of the atom or the ion. Electrons occupy most of the space of the atom or ion.
If there are more than one electrons, they would be located in one or more main energy levels. Generally, for two atoms/ions with a similar number of protons, the one with more filled main electron shells would have a larger radius.
Electrons in a neutral Na atom occupy three main energy shells. The outermost shell contains only one electron. That electron would be removed first, such that in the Na⁺ ion, electrons would occupy only two main shells.
Similarly, electrons in a neutral K atom occupy four main energy shells. The outermost shell contains only one electron. That electron would be removed first, such that in the K⁺ ion, electrons would occupy three main shells.
Since there are more occupied electrons shells in K⁺ than in Na⁺, K⁺ would have a larger ionic radius.
Hi there!
There is a total of 22 atoms in this compound. (Add all the numbers)
Could you Brainliest me, please?
The process involving separation of liquid/solid mixture as regards this question is Decantation.
- Decantation can be regarded as one of the process used in separation of liquid from solid as well as other immiscible (non-mixing) liquids through the removal of the liquid layer that is present at the top from the layer of solid/liquid which present at the below.
- In the process, the liquid will be poured slowly into another vessel as the pouring continues, then the solid will settle in the original vessel.
- This process can be done through tilting the mixture after the the top layer have been poured out.
<em>Therefore, decantation is one of the separation technique.</em>
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Sound spreads in the medium in the form of concentric spheres known as wave-fronts.
Now, as each wave-front expands, it moves away from the source of the sound and expands at a wider space. This means that its energy decreases and the sound becomes quieter.
So, overall, as sound spreads in spheres:
1- The energy per wave decreases
2- The amplitude of the wave decreases
3- The sound becomes quieter as the sphere moves further away from the source
Hope this helps :)<span />
Answer:
Dipole-dipole attractions
Explanation:
PBr₃ is a <em>trigonal pyramidal</em> molecule.
The P-Br bonds are polar, with their bond dipoles pointing toward the Br atoms (see below).
The x-components of the dipoles cancel, but the y-components reinforce each other.
The partially negative Br atoms are attracted to the partially positive N atoms in neighboring molecules.
These dipole-dipole forces are the strongest intermolecular forces in PBr₃.