A mover loads a 100 kg box into the back of a moving truck by
1 answer:
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Answer:
a) R(fw) = 46.75*10⁶ (N)
b) R(rwi) = 70.125*10⁶ [N]
Explanation: See Attached file (the rectangle stands for a jet)
The diagram shows forces acting on the jet
Let R(fw) Reaction of front wheels and
R(rw) Reaction of rear wheels
Now we apply the Stevin relation, for R(fw) and a jet weight as follows
R(fw)/ 4 = 187*10⁶ / 16
Then :
R(fw) = ( 1/4) *187*10⁶ ⇒ R(fw) = 46.75*10⁶ (N)
And e do the same for the reaction on rear wheels
R(rw) / 12 = 187*10⁶ /16 ⇒ R(rw) =(3/4)*187*10⁶
R(rw) = 140,25*10⁶ [N]
The last expression is for the whole reaction, and must be devide by 2
because that force is exerted for two wheels, therefore on each of the two rear wheels the reaction will be:
R(rwi) = 70.125*10⁶ [N]
Answer:
The power consumed by the air filter is 9.936 watts
Explanation:
It is given that, the secondary coil of a step-up transformer provides the voltage that operates an electrostatic air filter.
Turn ratio of the transformer,
Voltage of primary coil,
Current in the secondary coil,
The power consumed by the air filter is :
...........(1)
For a transformer,
So,
So, the power consumed by the air filter is 9.936 watts. Hence, this is the required solution.