One mole of compound A, with vapor pressure 420mmHg at 50°C, mixed with 5 moles of compound B, with vapor pressure 480mmHg at 50 °C to form a homogeneous solution. What is the vapor pressure of mixture at 50°C?
1 answer:
Answer:
the vapor pressure of mixture at 50°C is 470 mm of Hg
Explanation:
The computation of the vapor pressure is shown below:
= (420 × 1 + 480 × 5) ÷ (1 + 5)
= (420 + 2400) ÷ (6)
= 2820 ÷ 6
= 470mm of Hg
Hence, the vapor pressure of mixture at 50°C is 470 mm of Hg
The same would be considered
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