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olya-2409 [2.1K]
2 years ago
14

A 0.060-kg tennis ball, moving with a speed of 5.50 m/s, has a head-on collision with a 0.090- kg ball initially moving in the s

ame direction at a speed of 3.00 m/s. Assuming a perfectly elastic collision, determine the speed and direction of each ball after the collision.
To the following:

1)Sketch. [Draw a sketch that represents the situation of the problem, while showing all the variables included in it (vectors or scalars as forces, velocity, displacement, position, etc.).]



2)Approach. [Mention all the laws, principles or concepts, as well as the mathematical equations that solve this problem. Step by step.]



3)Solution. [Develop the physical or mathematical equations used for the solution of the problem and highlight the partial and final answers. Be clear and organized.]
Physics
1 answer:
madreJ [45]2 years ago
8 0

Answer:

how possible is it to use figures to draw.

well, I don't know

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ELECTROMAGNETIC FIELDS PLAN AN INVESTIGATION LAB REPORT FOR EDG.!!!!! WORTH 100 POINTS????????
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Answer:ummm ok

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An oil droplet is sprayed into a uniform electric field of adjustable magnitude. The 0.11 g droplet hovers
ohaa [14]

Answer:

The direction of the field is downward, and negatively charged particles will experience an upwards force due to the field.

F = N e E     where E is the value of the field and N e the charge Q

M g = N e E      and M g is the weight of the drop

N = M g / (e E)

N = 1.1E-4 * 9.8 / (1.6E-19 * 370) = 1.1 * 9.8 / (1.6 * 370) * E15 = 1.82E13

.00011 kg is a very large drop

Q = N e = M g / E = .00011 * 9.8 / 370 = 2.91E-6 Coulombs

Check:     N = Q / e = 2.91E-6 / 1.6E-19 = 1.82E13   electrons

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Planet X is a terrestrial planet in our solar system. It has 21% oxygen in its atmosphere. Humans can walk on this planet withou
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2 years ago
Read 2 more answers
A negative charge, q1, of 6 µC is 0. 002 m north of a positive charge, q2, of 3 µC. What is the magnitude and direction of the e
prohojiy [21]

Force on the particle is defined as the application of the force field of one particle on another particle. The magnitude and direction of the electrical force will be 4.05×10⁴N towards the north.

<h3>What is electrical force?</h3>

Force on the particle is defined as the application of the force field of one particle on another particle. It is a type of virtual force.

The given data in the problem is

q₁ is the negative charge = 6 µC=6×10⁻⁶ C

q₂ is the positive charge = 3 µC=3×10⁻⁶ C

r is the distance between the charges=0.002 m

F_E is the electric force =?

The value of electric force will be;

\rm F_E= \frac{Kq_1q_2}{r^2} \\\\ F_E= \frac{9\times 10^9\times 6\times 10^{-6}\times3\times10^{-6}}{(0.002)^2}\\\\ \rm F_E=4.05\times10^4\;N

Hence the magnitude and direction of the electrical force will be 4.05×10⁴N towards the north.

To learn more about the electrical force refer to the link;

brainly.com/question/1076352

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2 years ago
What happens when an object is moved against gravity, such as rolling a toy car up a ramp?
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it goes up until we help it to but the moment we stop support it gets affected by gravity and goes back

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