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charle [14.2K]
3 years ago
14

a child's toy consists of a piece of plastic attached to a spring. the spring is compressed against the floor a distance of 2.0

cm and released. if the spring constant is 85 N/m, what is the magnitude of the spring force acting on the toy at the moment it is released.
Physics
1 answer:
Nat2105 [25]3 years ago
5 0

Answer:

1.7N

Explanation:

Force = kx

Where x = spring compression and

K = spring constant

K =85N/m

x = 2.0cm / 100

= 0.02m

Force = 85 x 0.02

= 1.7N

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Predestination, in theology, is the doctrine that all events have been willed by God, usually with reference to the eventual fate of the individual soul. Explanations of predestination often seek to address the "paradox of free will", whereby God's omniscience seems incompatible with human free will.
4 0
3 years ago
Read 2 more answers
A 35.9 g mass is attached to a horizontal spring with a spring constant of 18.4 N/m and released from rest with an amplitude of
lidiya [134]

Answer:

7.74m/s

Explanation:

Mass = 35.9g = 0.0359kg

A = 39.5cm = 0.395m

K = 18.4N/m

At equilibrium position, there's total conservation of energy.

Total energy = kinetic energy + potential energy

Total Energy = K.E + P.E

½KA² = ½mv² + ½kx²

½KA² = ½(mv² + kx²)

KA² = mv² + kx²

Collect like terms

KA² - Kx² = mv²

K(A² - x²) = mv²

V² = k/m (A² - x²)

V = √(K/m (A² - x²) )

note x = ½A

V = √(k/m (A² - (½A)²)

V = √(k/m (A² - A²/4))

Resolve the fraction between A.

V = √(¾. K/m. A² )

V = √(¾ * (18.4/0.0359)*(0.395)²)

V = √(0.75 * 512.53 * 0.156)

V = √(59.966)

V = 7.74m/s

8 0
3 years ago
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Suppose you are walking home after school. The distance from school to your home is five kilometers. On
Rudiy27
On foot= 1 kilometer per 5 minutes
Bike= I kilometer per 2 minutes
3 minutes fast per mile on bike
8 0
4 years ago
A machine lifts a 44,760 newton crate 2 meters into the air in 10 seconds. How many horsepower does the machine
VladimirAG [237]

Answer:

<u>8952 W</u>

Explanation:

<u>Given</u> :

  • Force = 44,760 Newtons
  • Displacement = 2 meters
  • Time taken = 10 seconds

<u>Equation</u>

  • Power = Work / Time
  • Power = Force x Displacement / Time

<u>Solving</u> :

  • P = 44760 x 2 / 10
  • P = 4476 x 2
  • P = <u>8952 W</u>
7 0
2 years ago
After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 48.0 cm . The explorer finds that
Ber [7]

Answer:

g = 12.22 m/s²

Explanation:

The time period of this pendulum is given as follows:

T = \frac{time\ taken}{no. of cycles}\\\\T = \frac{144\ s}{93}\\\\T = 1.55\ s

but the formula for the time period of a simple pendulum is as follows:

T=2\pi \sqrt{\frac{l}{g}}\\

where,

L = length of pednulum = 48 cm = 0.48 m

g = magnitude of th gravitational acceleration on this planet = ?

Therefore,

1.55\ s=2\pi \sqrt{\frac{0.48\ m}{g}}\\\\\sqrt{g} = 2\pi \sqrt{\frac{0.48\ m}{1.55\ s}}\\\\g = 3.49^{2}\\

<u>g = 12.22 m/s²</u>

6 0
3 years ago
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