Answer:
Here's what I get
Explanation:
1. Fluorine
a. Each fluorine atom has seven valence electrons.
b. Fluorine is a nonmetal.
c. The combination of these atoms creates a covalent bond.
d. The atoms share a pair of valence electrons.
e. In the ionic bond, an electron moved from one atom to the other one.
f. The molecule forms a straight line.
2. Oxygen
a. Each oxygen atom has six valence electrons.
b. Oxygen is a nonmetal.
c. The combination of these atoms creates a covalent bond.
d. The atoms share two pairs of valence electrons.
e. The bond has four electrons instead of two.
f. The molecule forms a straight line.
Answer:
Period
Explanation:
The name of the rows in the periodic table being period.
A column would be called a group/family.
1. gamma rays
2. C
3.D
4.A
5.A
6.A
7.B
8.some aplications would be the use of x-rays in medicine and the rsiation of food to preserve it
9.Both fission and fusion are nuclear processes by which atoms are altered to create energy, but what is the difference between the two? Simply put, fission is the division of one atom into two, and fusion is the combination of two lighter atoms into a larger one
10.The electroscope is a fairly simple device comprised of a metal rod with two thin leaves attached to one end. If the electroscope is given a negative charge, the metal leaves will separate from each other. It is this characteristic that makes the electroscope useful as a detection device. A negatively charged electroscope will discharge when ions in the air remove electrons from it, and consequently, a positively charged electroscope will discharge when it takes electrons from the air around it. The rate of discharge of the electroscope is a measure of ions in the air and can be used as a basis of measurement and detection
11. they are bigger and colide with atoms easier
Answer:
- A) pH = 2.42
- B) pH = 12.00
Explanation:
<em>The dissolution of HCl is HCl → H⁺ + Cl⁻</em>
- To solve part A) we need to calculate the concentration of H⁺, to do that we need the moles of H⁺ and the volume.
The problem gives us V=2.5 L, and the moles can be calculated using the molecular weight of HCl, 36.46 g/mol:
= 9.60*10⁻³ mol H⁺
So the concentration of H⁺ is
[H⁺] = 9.60*10⁻³ mol / 2.5 L = 3.84 * 10⁻³ M
pH = -log [H⁺] = -log (3.84 * 10⁻³) = 2.42
- <em>The dissolution of NaOH is NaOH → Na⁺ + OH⁻</em>
- Now we calculate [OH⁻], we already know that V = 2.0 L, and a similar process is used to calculate the moles of OH⁻, keeping in mind the molecular weight of NaOH, 40 g/mol:
= 0.02 mol OH⁻
[OH⁻] = 0.02 mol / 2.0 L = 0.01
pOH = -log [OH⁻] = -log (0.01) = 2.00
With the pOH, we can calculate the pH:
pH + pOH = 14.00
pH + 2.00 = 14.00
pH = 12.00
Answer:
HI (hydrogen iodide).
Explanation:
Hello,
In this case, since iodine is in group VIIA, it has seven valence electrons at its outer shell, which means that it only needs one bond to attain the octet. Moreover, since hydrogen has just one electron at its outer shell, one hydrogen turns out enough to obey the octet when hydrogen and iodine bond as shown below:
Therefore, the required formula is:
Which is hydrogen iodide.
Best regards.
