Question

Can anybody help meh :(

Answer 1

Answer:

$n=1.56\times 10^{17}$ electrons

Explanation:

Given that,

Total charge = 9 mC = 0.009 C

0.009 C of charge passes through a wire in 3.6 s.

Let q' is the charge that passes through it in 10 s.

So,

$\dfrac{0.009 }{3.6}=\dfrac{q'}{10}\\\\q'=\dfrac{0.009 \times 10}{3.6}\\\\q'=0.025\ C$

We know that,

q = ne

Where

n is the number of electrons

So,

$n=\dfrac{q}{e}\\\\n=\dfrac{0.025}{1.6\times 10^{-19}}\\\\n=1.56\times 10^{17}$

So, $1.56\times 10^{17}$electrons must pass through the cross-sectional area.