Explanation for x=73km/h•0.5s= 10.14 pls help how did they get 10.14? What was the work around it

A rocket is fired vertically upwards with initial velocity 92 m/s at the ground level. Its engines then fire and it is accelerat

Readme [11.4K]

Answer:

The rocket above the ground is in 44 sec.

Explanation:

Given that,

Initial velocity = 92 m/s

Acceleration = 4 m/s²

Altitude = 1200 m

Suppose, How long was the rocket above the ground?

We need to calculate the time

Using equation of motion

$s=ut-\dfrac{1}{2}at^2$

Put the value into the formula

$1200=92t+\dfrac{1}{2}\times4t^2$

$2t^2+92-1200=0$

$t=10\ sec$

We need to calculate the velocity

Using equation of motion

$v=u+at$

Put the value into the formula

$v=92+4\times10$

$v=132\ m/s$

When the rocket hits the ground,

Then, h'=0

We need to calculate the time

Using equation of motion

$h'=h+ut-\dfrac{1}{2}at^2$

Put the value into the formula

$0=1200+132t-\dfrac{1}{2}\times9.8t^2$

$4.9t^2-132t-1200=0$

$t=34\ sec$

When the rocket is in the air it is the sum of the time when it reaches 1000 m and the time when it hits the ground

So, the total time will be

$t'=34+10$

$t'=44\ sec$

Hence, The rocket above the ground is in 44 sec.

7 0

4 years ago

Learning Goal: To practice Problem-Solving Strategy 19.1 Work in Ideal-gas Processes. A cylinder with initial volume VVV contain

Leokris [45]

Answer:

The work done on the gas is equal to the area under the curve pv diagram w = area of triangle = 1/2 (base)(height) = 1/2 (BC)(Ac) = 1/2 (3v - v)(3p - p) = 1/2 (9 vp - 3 vp - 3vp + vp) = 4 vp/2 W = 2 vp

Check attachment for the diagrammatic representation

5 0

4 years ago

A person who is properly constrained by an over-the-shoulder seat belt has a good chance of surviving a car collision if the dec

postnew [5]

Answer:

Distance = 0.738 m

Explanation:

Solution:

First convert Km/h into m/s.

75 km/h * 1000 m/km * 1 hr/3600 sec = 20.8333 m/s

According to third equation of motion:

$Vf^{2}$ – $Vi^{2}$ = 2 * acceleration * distance

Vf= final velocity

Vi= initial velocity

putting values in third equation of motion....

$0.2^{2}$ – $20.8333^{2}$ = 2 * (-30 * 9.8) * distance

note:

negative sign is due to deceleration

Distance = 0.738 m

8 0

3 years ago

A horse pulls on a carriage. By Newton's third law, the carriage pulls back on the horse with equal force. Why do the action and

Andrews [41]

Answer:

By Newton's third law the cart must then exert an equal and opposite force on the horse. ... If it doesn't accelerate, and it started it rest, it must remain at rest (by the definition of acceleration), and therefore no matter how hard the horse pulls, it can never move the cart

5 0

3 years ago

a 40 kg boy jumps off the side of the pool. when he hits the water, he is traveling 3 m/s. how much kinetic energy does he have

Vladimir79 [104]

3 m/s because when he hits the water he will be traveling at the same speed

4 0

4 years ago