To determine which is the correct answer, we convert the mass of the compounds into units of particles of the compound. We use the molar masses and the Avogadro's number. We do as follows:
<span>76.9 g I2 (1 mol / 253.81 g) (6.022x10^23 particles / 1 mol ) = 1.82x10^23
79.9 g Br2 (1 mol / 159.81 g)</span>(6.022x10^23 particles / 1 mol ) = 3.011x10^23<span>
6 g C (1 mol / 12 g)</span>(6.022x10^23 particles / 1 mol ) = 3.011x10^23<span>
13.01 g CH4 ( 1 mol / 16.04 g )</span>(6.022x10^23 particles / 1 mol ) = 4.88x10^23 particles
Therefore, the answers are Br2 and C.
The answer is it tends to be more negative down a group. This is because as you go down the periodic table, the elements have more electron shells in their atoms. This makes the outermost shells less attracted to the nucleus due to their greater distances from the nucleus. Therefore, these shells are less likely to attract electrons (hence lower electron affinity) and are even more likely to lose electrons from their outer electron orbits.
Answer:
D) N-Cl.
Explanation:
The electronegativity of the elements in Group 5 (N. P As and Bi) decreases as we go down the Group so N is the most electronegative and chlorine is less able to draw electrons away from N than from the other elements in Group 5.
