Answer:
0.1066 hours
Explanation:
A common pesticide degrades in a first-order process with a rate constant (k) of 6.5 1/hours. We can calculate its half-life (t1/2), that is, the times that it takes for its concentration to be halved, using the following expression.
t1/2 = ln2/k
t1/2 = ln2/6.5 h⁻¹
t1/2 = 0.1066 h
The half-life of the pesticide is 0.1066 hours.
Answer:
Tile 52 and three are incorrect
Explanation:
Base pairs of DNA are A with T, and C with G
here's how to remember:
Apple - Tree
Car - Garage
Well electrons are like electricity well it is partly if it went 3 sub levels the electrons would blow up some electricty<span />
