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beks73 [17]
3 years ago
6

A ball is thrown straight up from point A, reaches a maximum height at point B, and then falls back to point C. Which of the fol

lowing is true about the ball’s velocity and acceleration the highest point B

Physics
1 answer:
ratelena [41]3 years ago
8 0
PE.....................
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A vertical scale on a spring balance reads from 0 to 155 N . The scale has a length of 10.0 cm from the 0 to 155 N reading. A fi
Harrizon [31]

Answer:

mass of the fish is 8.11 kg

Explanation:

As we know that the frequency of oscillation of spring block system is given as

f = \frac{1}{2\pi}\sqrt{\frac{k}{m}}

here we know that the reading of scale varies from 0 to 155 N from length varies from x = 0 to x = 10 cm

Now we have

k = \frac{155}{0.10} N/m

k = 1550 N/m

so now we have

2.20 = \frac{1}{2\pi}\sqrt{\frac{1550}{m}}

m = 8.11 kg

so mass of the fish is 8.11 kg

4 0
2 years ago
Daily life examples of pressure of solids on solids?​
Ipatiy [6.2K]

Explanation:

There's a massive amount, just think of anything everyday. Like a table on the floor, or when your walking around and putting pressure on the floor. When you squeeze something which is solid. Anything like that will do.

6 0
3 years ago
What is the definition magnitude?
strojnjashka [21]

Answer:

What is the definition magnitude?

Magnitude (mathematics), a measure of the size of a mathematical object.

xXxAnimexXx

Have a great day!

4 0
2 years ago
Read 2 more answers
What is the term for a motion you make on a touch screen with the tip of one or more fingers or your hand?
frozen [14]
Double tap, zoom in.

please vote my answer brainliest. thanks!
6 0
3 years ago
Consider a point charge qqq in three-dimensional space. Symmetry requires the electric field to point directly away from the cha
bonufazy [111]

Answer:

 E = \frac{1}{4\pi  \epsilon_o } \  r^2

Explanation:

For this exercise let's use Gauss's law. The Gaussian surface that follows the symmetry of the charges is a sphere

           Ф = ∫ E. dA = \frac{x_{int} }{\epsilon_o}

the bold are vectors, the radii of the sphere and the electric field are parallel therefore the scalar product reduces to the algebraic product

           Ф = ∫ E dA = \frac{x_{int} }{\epsilon_o}

           E ∫ dA = \frac{x_{int} }{\epsilon_o}

           E A = \frac{x_{int} }{\epsilon_o}

the area of ​​a sphere is

            A = 4π r²

the charge inside the sphere is q = + q

           

we substitute

           E 4π r² = \frac{x }{\epsilon_o}

           E = \frac{1}{4\pi  \epsilon_o } \  r^2

4 0
2 years ago
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