Answer: The velocity at different marked time points are given as
t1 = -
t2 = +
t3 = +
t4 = -
t5 = 0
Explanation:
The slope of the tangent of the curve indicates the instantaneous velocity. So if the slope of the tangent is positive, that Is, the tangent makes a positive angle (above the horizontal axis) with the horizontal
axis, then the velocity at this point is positive, and if the slope of the tangent is negative, that is the tangent makes a negative angle with the horizontal axis (below the horizontal axis), then the velocity at this point is negative.
When the tangent of the line is parallel to the horizontal axis, the velocity is 0.
From the position-time graph attached, the sign on the instantaneous velocity for each time marked on the graph is given below
t1 = -
t2 = +
t3 = +
t4 = -
t5 = 0
QED!
Eris is slightly more massive than Pluto. However, both of them are smaller than Earth's Moon.
This should conclude that Eris is a dwarf planet.
It causes or makes a magnetic field.
I hope my answer helped u under stand better
Answer:
A) E = 4.96 x 10³ eV
B) E = 4.19 x 10⁴ eV
C) E = 3.73 x 10⁹ eV
Explanation:
A)
For photon energy is given as:
![E = hv](https://tex.z-dn.net/?f=E%20%3D%20hv)
![E = \frac{hc}{\lambda}](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7Bhc%7D%7B%5Clambda%7D)
where,
E = energy of photon = ?
h = 6.625 x 10⁻³⁴ J.s
λ = wavelength = 0.25 nm = 0.25 x 10⁻⁹ m
Therefore,
![E = (7.95 x 10^{-16} J)(\frac{1 eV}{1.6 x 10^{-19} J})](https://tex.z-dn.net/?f=E%20%3D%20%287.95%20x%2010%5E%7B-16%7D%20J%29%28%5Cfrac%7B1%20eV%7D%7B1.6%20x%2010%5E%7B-19%7D%20J%7D%29)
<u>E = 4.96 x 10³ eV</u>
<u></u>
B)
The energy of a particle at rest is given as:
![E = m_{0}c^2](https://tex.z-dn.net/?f=E%20%3D%20m_%7B0%7Dc%5E2)
where,
E = Energy of electron = ?
m₀ = rest mass of electron = 9.1 x 10⁻³¹ kg
c = speed of light = 3 x 10⁸ m/s
Therefore,
![E = (9.1 x 10^{-31} kg)(3 x 10^8 m/s)^2\\](https://tex.z-dn.net/?f=E%20%3D%20%289.1%20x%2010%5E%7B-31%7D%20kg%29%283%20%20x%20%2010%5E8%20m%2Fs%29%5E2%5C%5C)
![E = (8.19 x 10^{-14} J)(\frac{1 eV}{1.6 x 10^{-19} J})\\](https://tex.z-dn.net/?f=E%20%3D%20%288.19%20x%2010%5E%7B-14%7D%20J%29%28%5Cfrac%7B1%20eV%7D%7B1.6%20x%2010%5E%7B-19%7D%20J%7D%29%5C%5C)
<u>E = 4.19 x 10⁴ eV</u>
<u></u>
C)
The energy of a particle at rest is given as:
![E = m_{0}c^2](https://tex.z-dn.net/?f=E%20%3D%20m_%7B0%7Dc%5E2)
where,
E = Energy of alpha particle = ?
m₀ = rest mass of alpha particle = 6.64 x 10⁻²⁷ kg
c = speed of light = 3 x 10⁸ m/s
Therefore,
![E = (6.64 x 10^{-27} kg)(3 x 10^8 m/s)^2\\](https://tex.z-dn.net/?f=E%20%3D%20%286.64%20x%2010%5E%7B-27%7D%20kg%29%283%20%20x%20%2010%5E8%20m%2Fs%29%5E2%5C%5C)
![E = (5.97 x 10^{-10} J)(\frac{1 eV}{1.6 x 10^{-19} J})\\](https://tex.z-dn.net/?f=E%20%3D%20%285.97%20x%2010%5E%7B-10%7D%20J%29%28%5Cfrac%7B1%20eV%7D%7B1.6%20x%2010%5E%7B-19%7D%20J%7D%29%5C%5C)
<u>E = 3.73 x 10⁹ eV</u>