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Degger [83]
3 years ago
8

How are ionic bonds formed?

Chemistry
2 answers:
AURORKA [14]3 years ago
7 0

Answer:

c

Explanation:

mario62 [17]3 years ago
3 0

Answer:

Same type of question from quizlet

But the answer is C

I hope you got it right :)

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In general, what is the effect of tempature on the solubility of a gas
kiruha [24]

Increased temperature causes an increase in kinetic energy. The higher kinetic energy causes more motion in the gas molecules which break intermolecular bonds and escape from solution.

3 0
3 years ago
A mixture of hept-1-yne, hept-2-yne, and hept-3-yne was hydrogenated in the presence of a platinum catalyst until hydrogen uptak
arsen [322]

Answer:

Only one seven carbon hydrocarbon was produced.

Explanation:

  • Alkynes are reduced completely in presence of Pt/H_{2} to produce alkanes.
  • Hydrogenation in presence of Pt is a simple nucleophilic addition process where H_{2} molecule adds onto an unsaturated bond.
  • Hept-1-yne, hept-2-yne and hept-3-yne are constitutionally isomeric to each other. Hence, after complete reduction, all three alkynes produced heptane as only product.
  • So, only one seven carbon hydrocarbon was produced.

4 0
3 years ago
Under what conditions is AG for a reaction always positive?
Rashid [163]
When H is positive and S is negative
6 0
3 years ago
PLEASE HELP ME NO LINKS
Y_Kistochka [10]

Answer: I don’t think the answer is A or C. Maybe B.

The word chemosynthesis means

the synthesis of organic compounds by bacteria or other living organisms using energy derived from reactions involving inorganic chemicals, typically in the absence of sunlight.

Explanation:

3 0
3 years ago
Read 2 more answers
3. A 31.2-g piece of silver (s = 0.237 J/(g · °C)), initially at 277.2°C, is added to 185.8 g of a liquid, initially at 24.4°C,
VARVARA [1.3K]

Answer:

Cp_{liquid}=2.54\frac{J}{g\°C}

Explanation:

Hello,

In this case, since silver is initially hot as it cools down, the heat it loses is gained by the liquid, which can be thermodynamically represented by:

Q_{Ag}=-Q_{liquid}

That in terms of the heat capacities, masses and temperature changes turns out:

m_{Ag}Cp_{Ag}(T_2-T_{Ag})=-m_{liquid}Cp_{liquid}(T_2-T_{liquid})

Since no phase change is happening. Thus, solving for the heat capacity of the liquid we obtain:

Cp_{liquid}=\frac{m_{Ag}Cp_{Ag}(T_2-T_{Ag})}{-m_{liquid}(T_2-T_{liquid})} \\\\Cp_{liquid}=\frac{31.2g*0.237\frac{J}{g\°C}*(28.3-227.2)\°C}{185.8g*(28.3-24.4)\°C}\\ \\Cp_{liquid}=2.54\frac{J}{g\°C}

Best regards.

6 0
3 years ago
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