Answer:
The normal force applied by block on the ground is (mg - F cosФ)
Explanation:
<em>Lets explain how to solve the problem</em>
At first you must distribute the force F into two components
<em>Vertical</em> component which is <em>F cosФ</em>
<em>Horizontal</em> component which is <em>F sinФ</em>
The block is in equilibrium, that means sum of forces acting on the
block is zero
So the upward forces equal the downward forces
Normal reaction force R applied by block on the ground and the
vertical component of F both are upward forces
The weight of the block is downward force
The normal reaction force R plus the vertical component of F is
equal to the weight
<em>R + F cosФ = W</em>
W = mg, where g is acceleration of gravity and m is the mass of
the block
<em>R + F cosФ = mg</em>
Subtract F cosФ from both sides
<em>R = mg - F cosФ</em>
<em></em>
The normal force applied by block on the ground is (mg - F cosФ)
Answer:
Explanation:
First we convert 2 cycles/s to angular velocity knowing that each circle has an angle of 2π
Then we calculate the moment of inertia of the cylindrical shell, assuming there's no mass inside the wheel (only at the rim):
So the kinetic energy of this is
Answer:
A material displaying ferromagnetism, such as the various forms of iron, steel, cobalt, nickel, and their alloys.
Explanation:
Answer:
3
Explanation:
During a crash 3 types of collisions can occur.
<span>(3) electromagnetic energy and internal energy</span>
