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3 years ago

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An astronaut on a strange planet finds that she can jump a maximum horizontal distance of 14.0 m if her initial speed is 2.20 m/

s. what is the free-fall acceleration on the planet? (ignore air resistance.)

1 answer:

pochemuha3 years ago

3 0

We have the equation of motion

$v^2 = u^2+2as$ , where v is the final velocity, u is the initial velocity, a is the acceleration and s is the displacement.

In this case initial velocity = 2.20 m/s, final velocity = 0 m/s, displacement = 14 m

On substitution we will get 0 = $2.20^2+2*a*14$

On solving we can find the acceleration value as -0.173 $m/s^2$

So free fall acceleration = 0.173 $m/s^2$

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a)

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b)

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$p(xg)$

$p(x$

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$p(x$

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Generally the mean and standard deviation of sample size is mathematically given by

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