Question

An astronaut on a strange planet finds that she can jump a maximum horizontal distance of 14.0 m if her initial speed is 2.20 m/s. what is the free-fall acceleration on the planet? (ignore air resistance.)

Answer 1

We have the equation of motion

                          $v^2 = u^2+2as$ , where v is the final velocity, u is the initial velocity, a is the acceleration and s is the displacement.

In this case initial velocity = 2.20 m/s, final velocity = 0 m/s, displacement = 14 m

On substitution we will get 0 = $2.20^2+2*a*14$

On solving we can find the acceleration value as -0.173$m/s^2$

So free fall acceleration = 0.173$m/s^2$