Answer:
8. acceleration = 
= 1 unit .
9. acceleration = = -1 unit.
10. acceleration = = 0 units.
Explanation:
8. i) acceleration = velocity / time
ii) In this figure velocity = time
iii) therefore acceleration = = 1 unit .
9. i) acceleration = velocity / time
ii) In this figure 4 = m + 5, therefore m = -1
therefore velocity = (-0.5 
time) + 5
iii) therefore acceleration = = -1 units.
10.) velocity is constant at 2
therefore acceleration = = 0 units
D. Assuming that it doesn’t accelerate and then decelerate between seconds.
Answer:
The frequencies the other string could have are 258.4 Hz and 261.6 Hz.
Explanation:
Given;
beat frequency, Fb = 1.60 Hz
frequency of the first string, F₁ = 260.00 Hz
frequency of the second string, F₂ = ?
Beat frequency is given as;
Fb = F₂ - F₁ or Fb = F₁ - F₂
Fb + F₁ = F₂ or F₂ = F₁ - Fb
1.6 + 260 = F₂ or F₂ = 260 - 1.6
261.6 Hz = F₂ or F₂ = 258.4 Hz
Therefore, the frequencies the other string could have are 258.4 Hz and 261.6 Hz.
