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Jlenok [28]
3 years ago
13

Can a metallic sphere be charged without rubbing​

Physics
1 answer:
morpeh [17]3 years ago
6 0
We need to charge a metal sphere positively without touching it. This can be achieved using electrostatic induction.
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A car that increase its speed from 20 km/h to 100 km/h undergoes -------acceleration,
stepladder [879]

negative acceleration- deceleration

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4 years ago
Important things about emotional health
atroni [7]

Answer:

The important thing about emotional health is being in control of their thoughts, feelings, and also behaviors.

Explanation:

Emotional health is an important part of overall health. People who are emotionally healthy are in control of their thoughts, feelings, and behaviors. They're able to cope with life's challenges. They can keep problems in perspective and bounce back from setbacks.

4 0
3 years ago
Read 2 more answers
uniformly charged conducting sphere of 1.2 m diameter has surface charge density 8.1 mC/m2. Find (a) the net charge on the spher
Stels [109]

Answer:

(a) = 3.7 × 10⁻⁵

(b) = 4.1 × 10⁻⁶ N.M²/C

Explanation:

(a) Diameter of the sphere, d = 1.2 m

Radius of the sphere, r = 0.6 m

Surface charge density, = 8.1 mC/m2 = 8.1 × 10⁻⁶ C/m²

Total charge on the surface of the sphere,

Q = Charge density × Surface area

    = 4πr²σ

   = 4 (3.14) (0.12²) (8.1 × 10⁻⁶)

   = 3.66 × 10⁻⁵C

   ≅ 3.7 × 10⁻⁵C

Therefore, the net charge on the sphere is  3.7 × 10⁻⁵C

(b)

Total electric flux (∅)

=Q / ε₀

ε₀ =  8.854 × 10⁻¹² N⁻¹C² m⁻²

Q =   3.66 × 10⁻⁵C

 =  3.66 × 10⁻⁵ / 8.854 × 10⁻¹²

= 4.1 × 10⁻⁶ N.M²/C

5 0
3 years ago
Plzz answer this correctly
AysviL [449]

Answer:

C and E...................

4 0
3 years ago
A simple harmonic transverse wave is propagating along a string towards the left direction as shown in the figure. figure shows
dimulka [17.4K]

Answer:

  1. Amplitude  = 5 cm (Heights)
  2. Wavelength (λ)  = 40 cm
  3. Wave speed (v) = 12 m/s (Approx)
  4. Time period (T) = 0.033 s (Approx)
  5. Maximum particle speed (V) = 9.43 m/s

Explanation:

1) Amplitude

Amplitude  = 5 cm (Heights)

2) Wavelength (λ)

Wavelength (λ)  = 40 cm

3) Wave speed

Wave speed (v) = √ t / μ

Wave speed (v) = √ 3.6 / [25x10⁻³]

Wave speed (v) = 12 m/s (Approx)

4) Time period (T)

Time period (T) = 1/f = (λ)/v

Time period (T) = 0.40m / 12

Time period (T) = 0.033 s (Approx)

5) Maximum particle speed (V)

Maximum particle speed (V) = Aw

Maximum particle speed (V) = [0.05x2x3.14] / 0.033

Maximum particle speed (V) = 9.43 m/s

6 0
3 years ago
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