The Earth's orbital period change is A: It would increase by 0.15 years
Using Kepler's third law which states that the square of the orbital period of the planet is directly proportional to the cube of its distance from the sun.
So, T² ∝ R³
T'²/T² = R'³/R³ where
- T = orbital period at R = 1 year
- R = initial axis length = 1 AU
- T' = orbital period at R'
- R' = final axis length = 1.1 AU.
So, making T' subject of the formula, we have
T' = [√(R'/R)³]T
T' = [√(1.1 AU/1 AU)³] × 1 year
T' = [√(1.1)³] × 1 year
T' = √1.331 × 1 year
T' = 1.15 × 1 year
T' = 1.15 years.
So, the change in the Earth's orbital period ΔT = T' - T
= 1.15 years - 1 year
= 0.15 years
Since this is positive, the orbital period <u>increases</u> by 0.15 years.
So, the Earth's orbital period change is A: It would increase by 0.15 years
Learn more about Kepler's third law here:
brainly.com/question/16546004
He must throw the device AWAY from the ship.
Since momentum is conserved, that move will give HIM an equal amount of momentum TOWARDS the ship.
The units of his measurement is newtons.