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Juli2301 [7.4K]
3 years ago
8

What is the maximum height a 95 W motor may vertically lift a 120 N weight in 6.2 s?

Physics
1 answer:
leva [86]3 years ago
4 0

Answer:

a. 4.9 m

Explanation:

To solve this problem we must take into account that power is defined as the relationship between the work and the time in which the work is done.

P = W/t

where:

P = power = 95 [W] (units of watts)

W = work [J] (units of Joules)

t = time = 6.2 [s]

We can clear the work from the previous equation.

W = P*t

W = 95*6.2 = 589 [J]

Now we know that the work is defined by the product of the force by the distance, therefore we can express the work done with the following equation.

W = F*d

where:

F = force = 120 [N] (units of Newtons)

d = distance [m]

d = W/F

d = 589/120

d = 4.9 [m]

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4 0
3 years ago
A truck is traveling at 2.0 m/s. It slows to a stop at a constant rate over 3.00 s. How far does the car travel during those 3.0
earnstyle [38]

Answer:

During those 3.00 seconds before stopping, the car travels a distance of 6 m.

Explanation:

The simple rule of three is a tool that is used to quickly solve problems, where three pieces of information must be known, and one of them operates as an unknown to be known.

Two magnitudes are directly proportional if one magnitude increases the other also does it, and if the magnitude decreases the other in the same way.

Being a, b and c known data and x the unknown, the value that we want to know, the rule of three when the magnitudes are directly proportional is applied as follows:

a ⇒ b

c ⇒ x

So: x=\frac{c*b}{a}

In this case, knowing that a truck travels at 2 m/s, the rule of three applies as follows: if in 1 second the truck travels 2 m, in 3 seconds how much distance does it travel?

distance=\frac{3 s*2 m}{1 s}

distance= 6 m

<u><em> During those 3.00 seconds before stopping, the car travels a distance of 6 m.</em></u>

8 0
4 years ago
A train runs from New Delhi to Hyderabad it covers first of 420 km in 7 hours and the next distance of 360 km in 6 hours​
Mkey [24]

Explanation:

the answer is 16.7 miles or 60kmph

5 0
3 years ago
Read 2 more answers
Runner A is initially 6.0 km west of a flagpole and is running with a constant velocity of 9.0 km/h due east. Runner B is initia
Eduardwww [97]

Answer:

From the data we know that runner A and runner B are 11 km apart from the start because (6+5) km

So the runner from the east direction has distance as unknown km, rate= 9 k/h ; time= d/r=x/9 hr

So runner towards the west will be

distance = 11-x, rate= 8 k/h, time = d/r = (11-x)/8

So equating east and west time we have

x/9= (11-x)/8

8x=99-9x

17x=99

x=5.92 km

That is the distance covered by runner towards the east and he will meet the runner toward the west at

6-5.92=0.08 km west of the flagpole.

7 0
4 years ago
PLS HELP ME!!! Explain frame of reference. How is it different when you are riding inside a car or standing by the highway?
RSB [31]

Answer:

So when you are riding in a car everything you see is from the cars frame. Where if you are standing by the highway it is from your point of view.

Explanation:

So lets say someone sees a apple core outside the bus it looks like the apple is traveling the opposite way of the bus but to the man standing by the highway would say it is stationary.

4 0
3 years ago
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