Answer:
27.22 dm³
Explanation:
Given parameters:
number of moles = 1 mole
temperature= 50°C, in K gives 50+ 273 = 323K
Pressure= 98.6kpa in ATM, gives 0.973 ATM
Solution:
Since the unknown is the volume of gas, applying the ideal gas law will be appropriate in solving this problem.
The ideal gas law is mathematically expressed as,
Pv=nRT
where P is the pressure of the gas
V is the volume
n is the number of moles
R is the gas constant
T is the temperature
Input the parameters and solve for V,
0.973 x V = 1 x 0.082 x 323
V= 27.22 dm³
Kdd was he e shxiuw r thai ed
Answer:
The answer to your question is:
1.- CO
2.- 0.414 moles of CO2
Explanation:
Data
2CO + O2 ⇒ 2CO2
CO = 0.414 moles
O2 = 0.418
Process
theoretical ratio CO/O2 = 2/1 = 1
experimental ratio CO/O2 = 0.414/0.418 = 0.99
Then the limiting reactant is CO
2.-
2 moles of CO --------------- 2 moles of CO2
0.414 moles of CO --------- x
x = (0.414 x 2) / 2
x = 0.414 moles of CO2
<h2><em>1. A</em></h2><h2><em>3. B</em></h2><h2><em>4. C</em></h2><h2><em>7. E</em></h2><h2><em>5. F</em></h2>
