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vagabundo [1.1K]
4 years ago
8

how did the occurrence of the supernova help support galileo's view that earth was not the center of the universe

Chemistry
1 answer:
yawa3891 [41]4 years ago
3 0
<span>The supernova of 1604 was observed in Padua on 10 October 1604 but on account of cloudy weather Galileo did not see it until a few days later. The supernova created great excitement and Galileo, who taught mathematics and astronomy at the University, was asked to give three public lectures that were attended by a large audience. In this paper we show how Galileo explained the nature of parallax in order to demonstrate that the new star was well beyond the Moon. We also consider his attempt to determine the nature of the star, and the amusing pamphlet that he penned to lampoon professional philosophers who denied that new stars could appear in the heaven
.
back at it again with the answer
.
Zane</span>
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If a 60-g object has a volume of 30 cm3, what is its density? 2 g/cm3 0.5 cm3/g 1800 g * cm3 none of the above
jasenka [17]

Answer : The density of an object is, 2g/cm^3

Solution : Given,

Mass of an object = 60 g

Volume of an object = 30cm^3

Formula used :

\text{Density of an object}=\frac{\text{Mass of an object}}{\text{Volume of an object}}

Now put all the given values in this formula, we get the density of an object.

\text{Density of an object}=\frac{60g}{30cm^3}=2g/cm^3

Therefore, the density of an object is, 2g/cm^3

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3 years ago
Which college classes would a student most likely take to become an oceanographer? Select 4 choices.
Setler [38]

Answer:

marine biology

coastal ecology

astronomy

meteorology

Explanation:

As a college student, to study oceanography one will have to take classes in the field of marine biology, coastal ecology, astronomy and meteorology.

An oceanographer is someone or a professional that studies the ocean in order have more scientific knowledge about them.

Oceanography is a merger of geology, biology, chemistry, physics as it pertains to the ocean.

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5 0
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The work function is the energy that must be supplied to cause the release of an electron from a photoelectric material. The cor
vladimir2022 [97]

Answer:

No photoelectric effect is observed for Mercury.

Explanation:

From E= hf

h= Plank's constant

f= frequency of incident light

Threshold Frequency of mercury= 435×10^3/ 6.6×10^-34 × 6.02×10^23

f= 11×10^14 Hz

The highest frequency of visible light is 7.5×10^14. This is clearly less than the threshold frequency of mercury hence no electron is emitted from the mercury surface

3 0
4 years ago
P4 + O₂<br> .P₂ Oz<br> what is the balance
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I am not sure sorry
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