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ZanzabumX [31]
3 years ago
12

____________ limits or stops the growth of bacteria.

Chemistry
2 answers:
Butoxors [25]3 years ago
6 0
ANSWER: Vaccine


Explanation: I had this question and got it right

Kaylis [27]3 years ago
3 0

Answer:

Vaccines

Explanation:

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I need help with my science project someone help me answer it!
GREYUIT [131]

Answer:

food

Explanation:

6 0
3 years ago
PLS HELP ME WITN THIS ILL GIVE BRAINLIEST
pantera1 [17]

A chemical property of a substance is a certain characteristic that can only be observed by participating in a chemical reaction. Alternatively, a chemical property of a substance is something that can only be observed when the substance undergoes a chemical change.

I'm not sure what you're supposed to do with the first four boxes; all four are examples of chemical properties. Do you have to name the specific type of chemical property as given in the description? If so, the following would be my answers:

Flammability/Combustibility: The ability of a substance to burn.

The next two are quite strange; I'm not aware of a term that cleanly describes reactivity with water or acid. I suspect that, given the level of the material here, the general property of "reactivity" might be the answer for both the second and third descriptions

(Water-)reactivity: Some substances react when put in water.

(Acid-)reactivity: Some substances react when put in acid.

Light sensitivity: Light can interact with some things to form new substances.

As for the chart, I've filled it in as shown in the attached image. Please take care to double-check what I've written; in particular, when it comes to the property, I might have used a different term from what you were taught in class or provided in some other resource that I don't have access to. I've also color-coded qualitative/quantitative and physical/chemical for your convenience.

3 0
3 years ago
At 400 K oxalic acid decomposes according to the reaction:H2C2O4(g)→CO2(g)+HCOOH(g)In three separate experiments, the intial pre
padilas [110]

Answer:

v = 2,66x10⁻⁵ P[H₂C₂O₄]

Explanation:

For the reaction:

H₂C₂O₄(g) → CO₂(g) + HCOOH(g)

At t = 0, the initial pressure is just of H₂C₂O₄(g). At t= 20000 s, pressures will be:

H₂C₂O₄(g) = P₀ - x

CO₂(g) = x

HCOOH(g) = x

P at t=20000 is:

P₀ - x + x + x = P₀+x. That means P at t=20000s - P₀ = x

For 1st point:

x = 92,8-65,8 = 27

Pressure of H₂C₂O₄(g) at t=20000s: 65,8-27 = 38,8

2nd point:

x = 130-92,1 = 37,9

H₂C₂O₄(g): 92,1 - 37,9 = 54,2

3rd point:

x = 157-111 = 46

H₂C₂O₄(g): 111-46 = 65

Now, as the rate law is :

v = k P[H₂C₂O₄]

Based on integrated rate law, k is:

(- ln P[H₂C₂O₄] + ln P[H₂C₂O₄]₀) / t = k

1st point:

k = 2,64x10⁻⁵

2nd point:

k = 2,65x10⁻⁵

3rd point:

k = 2,68x10⁻⁵

The averrage of this values is:

k = 2,66x10⁻⁵

That means law is:

v = 2,66x10⁻⁵ P[H₂C₂O₄]

I hope it helps!

4 0
3 years ago
Help mee please (I will give the person who answers this a brainlist)
Leokris [45]
2 5 3 4 1 is the answers
7 0
3 years ago
Read 2 more answers
Which factor affects a solute's solubility rather than its rate of solution?
Illusion [34]

Answer: A

Explanation:

I took the test it was A

4 0
3 years ago
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