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ZanzabumX [31]
2 years ago
12

____________ limits or stops the growth of bacteria.

Chemistry
2 answers:
Butoxors [25]2 years ago
6 0
ANSWER: Vaccine


Explanation: I had this question and got it right

Kaylis [27]2 years ago
3 0

Answer:

Vaccines

Explanation:

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aivan3 [116]

$14.00

fee for a Law and rule book

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2 years ago
What are three ways of the atmosphere is important to living things?
UNO [17]
  <span>1. Blocks Ultra violet rays that can be harmful.
2. Provides Oxygen, so we can live. 
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7 0
2 years ago
I’m struggling with dimensional analysis in chemistry! Will someone please help me with .74 Kcal/min to cal/sec ? Explain and gi
valina [46]

Answer:

            12.33 cal/sec

Explanation:

As we know,

                          1 Kcal  =  1000 cal

So,

                     0.74 Kcal  =  X cal

Solving for X,

                      X =  (0.74 Kcal × 1000 cal) ÷ 1 Kcal

                      X =  740 cal

Also we know that,

                      1 Minute  =  60 Seconds

Therefore, in order to derive cal/sec unit replace 0.74 Kcal by 740 cal and 1 min by 60 sec in given unit as,

                                       = 740 cal / 60 sec

                                       = 12.33 cal/sec

3 0
3 years ago
Compute the equilibrium constant,K, at 25 ∘C for the reaction between Ni2+(aq) and Zn(s), which form Ni(s) and Zn2+(aq)
ANEK [815]

Answer:

The answer to the question is;

The equilibrium constant,K, at 25 °C for the reaction between Ni²⁺(aq) and Zn(s), which form Ni(s) and Zn²⁺ is 2.04×10¹⁷.

Explanation:

The half reactions are as follows

Ni²⁺ (aq) + 2e⁻ -> Ni (s)

Zn (s) -> Zn²⁺ (aq) + 2e⁻

For the Ni²⁺/Ni system we have the potential given as -0.23V (Reduction)

For the Zn²⁺/Zn sytem, the potential is -0.76. Here however, we should note that the zinc is being oxidized and therefore the potential is positive, that is;

Zn/Zn²⁺ = 0.76

Therefore the voltage for the sum of the reactions on both sides of the process is

-0.23 V + 0.76 V = 0.53 V    

We then call upon the Nernst equation to calculate the equilibrium constant as follows

E⁰_{cell} = \frac{0.0592}{n} logK

Where:

E⁰_{cell} = Standard cell potential = 0.53 V

n = Number of moles of electrons = 2 moles of e⁻

K = Equilibrium constant

Therefore we have

0.53 V = \frac{0.0592}{2} logK

Therefore log K = 17.905

and K =   10^{17.9054} = 2.04×10¹⁷.

5 0
3 years ago
Read 2 more answers
Which reaction takes place in a nuclear fission reactor?
Aleonysh [2.5K]

Answer:

It’s C I think Explanation:

7 0
3 years ago
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