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Nimfa-mama [501]
3 years ago
10

A graph titled Position versus time for with horizontal axis time (seconds) and vertical axis position (meters). A straight blue

line runs with an upward slope from 0 seconds 3 meters to 4 seconds 15 meters.
The starting position of this object is
(blank) m.

The object is traveling at a velocity of
(blank) m/s.
Physics
1 answer:
ankoles [38]3 years ago
6 0

Answer:

starting position: 3 m

velocity: 3 m/s

Explanation:

at t=0 position= 3 m

velocity: (delta)position/(delta)time

(delta=change in)

velocity= (15-3)/(4-0)

velocity= 12/4

velocity= 3 m/s

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If a 100 N net force act on a 50-kg car, what will the acceleration be
inna [77]
Acceleration = force / mass.

A = 100/50 = 2 m/s^2 .
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3 years ago
A concave mirror has a focal length of 30.0 CM. an object is placed 15.0 CM from the mirror. what is the radius of curvature of
Nana76 [90]

Answer:

60 cm

Explanation:

We are given;

  • Focal length of a concave mirror as  30.0 cm
  • Object distance is 15.0 cm

We are required to determine the radius of curvature.

We need to know that the radius of a curvature is the radius of a circle from which the curved mirror is part.

We also need to know that the radius of curvature is twice the focal length of a curved mirror.

Therefore;

Radius of curvature = 2 × Focal length

Therefore;

Radius of curvature = 2 × 30 cm

                                 = 60 cm                                  

7 0
3 years ago
A person just supports a mass of 20kg suspended from a rope.
Georgia [21]

Answer:

F = 200 N

Explanation:

Given that,

The mass suspended from the rope, m = 20 kg

We need to find the resultant force acting on the rope. The resultant force on the rope is equal to its weight such that,

F = mg

Where

g is acceleration due to gravity

Put all the values,

F = 20 kg × 10 m/s²

F = 200 N

So, the resultant force on the mass is 200 N.

7 0
3 years ago
Equipotential surfaces a) make an angle of 45 degrees with the electric field. b) are parallel to the electric field. c) are per
Schach [20]

Answer:

Option c) are perpendicular to the electric field

Explanation:

Equipotential surfaces are perpendicular to the electric field. the electric field lines are projected outwards from the equipotential surface, i.e., the lines of the electric field are at 90^{\circ} to the equipotential surface.

Equipotential surface are those surfaces that have the same potential at any point on the surface. Thus the potential difference at any point on the surface is zero due to same potential.

Any charge particle on this surface will move in a perpendicular direction to the Coulombian force. No work is done by the force on a particle moving on an equipotential surface.

7 0
3 years ago
A student obtained a clean dry glass-stoppered flask. she weighed the flask and stopper on an analytical balance and found the t
svetoff [14.1K]
29.213 cm3


First, calculate the mass of the water used. You do this by subtracting the original mass of the flask from the combined mass of the water and flask, giving:60.735 g - 31.601 g = 29.134 g
So we now know we have 29.134 g of water. To calculate the volume of the flask, simply divide by the density of the water, giving:29.134 g / (0.9973 g/cm3) = 29.213 cm3
6 0
3 years ago
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