By showing what resources the planet had to offer
Explanation:
Carbon dioxide isn't a polar molecule because
same nature of charge appears in opposite direction which cancel each other. So, carbon dioxide is non-polar molecule.
Answer:
Explanation:
Increasing Volume while maintaining constant pressure requires a proportional increase in Temperature so the gas pressure will be maintained as constant.
Consider...
V₁ = V₁ V₂ = 4V₁
T₁ = T₁ T₂ = ?
Charles Law => T ∝ V at constant P ... that is, increasing temperature generates a proportional increase in volume to maintain constant pressure.
Empirical Charles Law Relation is ...
V₁/T₁ = V₂/T₂ => T₂ = T₁(V₂/V₁) = T₁(4V₁/V₁) = 4T₁
Increasing Volume of a gas by 4 times requires a 4 times increase in absolute temperature in order to maintain constant pressure.
Answer:
The pressure inside the flask is 0,09 atm
Explanation:
We calculate the number of moles of O2, we convert the Temperature into unit KELVIN and use the formula of the ideal gases to calculate the pressure:
Weight 1 mol of 02= 15,999g x2= 32g
32g---1mol 02
0,60g---x=(0,60gx1mol O2)/32g= 0,019mol O2
T(K)=273+22=295K
PV=nRT
Px5.0l= 0,019mol x 0,082 lxatm/Kxmolx295 K
P=(0,019mol x 0,082 lxatm/Kxmolx295 K)/5.0l
P=0,09atm
Answer:
64799.4 J
Explanation:
The following data were obtained from the question:
Mass (M) = 1.05 kg = 1.05 x 1000 = 1050g
Specific heat capacity (C) = 0.9211 J/g°C
Initial temperature (T1) = 23°C
Final temperature (T2) = 90°C
Change in temperature (ΔT) = T2 – T1 =
90°C – 23°C = 67°C
Heat required (Q) =....?
The heat required to increase the temperature of the kettle can b obtain as follow:
Q = MCΔT
Q = 1050 x 0.9211 x 67
Q = 64799.4 J
Therefore, 64799.4 J of heat is required to increase th temperature of the kettle from 23°C to 90°C.
