Answer:
Hi... U should do like this
5 - 3.5=1.5 (N)
When carbon is burned in air carbon iv oxide gas is formed.
C (s) + O2 (g) = CO2(g) ΔH = - 393.5 kj/mol
The enthalpy change of the reaction is -393.5 j/mol which means that when one mole of carbon is completely burnt in air then 393.5 j of energy is evolved.
Thus, 1 mole = -393.5 j , then for 480 kj
= 480 × 1/393.5
= 1.2198 moles
1 mole of carbon iv oxide is equal to 44 g
thus, 1.2198 moles will be 1.2198 × 44 = 53.6712 g of CO2
Answer:
We have:
M
g
(
s
)
+
H
C
l
(
a
q
)
→
M
g
C
l
2
(
a
q
)
+
H
2
(
g
)
LHS
Mg= 1
H= 1
Cl= 1
RHS
Mg= 1
Cl=2
H=2
To make Cl and H have 2 on both sides, we place a 2 in front of the HCl
M
g
(
s
)
+
2
H
C
l
(
a
q
)
→
M
g
C
l
2
(
a
q
)
+
H
2
(
g
)
LHS
Mg=1, H=2, Cl=2
RHS
Mg=1, H=1, Cl=2
Thus the equation is balanced and the coefficient of Mg is 1, which is understood so it is not written in the final equation.
Explanation:
