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Rina8888 [55]
3 years ago
14

What is the strongest intermolecular force present in HCl?

Chemistry
1 answer:
Agata [3.3K]3 years ago
7 0

Answer:

Dipole dipole interaction

Explanation:

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What does the answer of element 3Na2S2O3?
Fynjy0 [20]

Answer:

Explanation:

3× 22+2×32+ 6×16=

66+64+96=236

4 0
3 years ago
Suppose you need 7.0 m of Grade 70 tow chain, which has a diameter of 38" and weighs , 2.16/kgm to tow a car. How would you calc
STatiana [176]

Answer : The mass of 7.0 m chain is, 15.12 kg

Explanation :

As we are given that,

The weight of the chain per unit length = 2.16 kg/m

Now we have to determine the mass of chain for 7.0 m length.

As, the mass of 1 m length of chain = 2.16 kg

So, the mass of 7.0 m length of chain = \frac{7.0m}{1m}\times 2.16kg

                                                                = 15.12 kg

Therefore, the mass of 7.0 m chain is, 15.12 kg

3 0
3 years ago
The equilibrium constant is given for two of the reactions below. Determine the value of the missing equilibrium constant. 2A(g)
monitta

Answer:

The value of the missing equilibrium constant ( of the first equation) is 1.72

Explanation:

First equation: 2A + B ↔ A2B   Kc = TO BE DETERMINED

 ⇒ The equilibrium expression for this equation is written as: [A2B]/[A]²[B]

Second equation: A2B + B ↔ A2B2   Kc= 16.4

⇒ The equilibrium expression is written as: [A2B2]/[A2B][B]

Third equation:  2A + 2B ↔ A2B2     Kc = 28.2

⇒ The equilibrium expression is written as: [A2B2]/ [A]²[B]²

If we add the first to the second equation

2A + B + B ↔ A2B2   the equilibrium constant Kc will be X(16.4)

But the sum of these 2 equations, is the same as the third equation ( 2A + 2B ↔ A2B2)   with Kc = 28.2

So this means: 28.2 = X(16.4)

or X = 28.2/16.4

X = 1.72

with X = Kc of the first equation

The value of the missing equilibrium constant ( of the first equation) is 1.72

7 0
4 years ago
Describe the motion of the gas particles.
Zepler [3.9K]
The particles in a solid are tightly packed and locked in place. ... The particles in a liquid are close together (touching) but they are able to move/slide/flow past each other. The particles in a gas are fast moving and are able to spread apart from each other.
6 0
3 years ago
Read 2 more answers
An aspirin tablet weighing 0.400 g has been analyzed and contains 68.2% acetylsalicylic acid (ASA) (180.16 g/mol) by mass. A stu
bogdanovich [222]

Answer:

0.00018M

Explanation:

Mass of the aspirin tablet =0.4g.

% by mass of ASA=68.2

mass of in the tablet=68.2/100×0.4g

=0.2748g

mass conc of ASA=mass of ASA/Volume of diluent(250ml)

=0.2748/0.25

=1.0992g/dm3

molar conc=mass conc/molar mass

=1.0992/180.16

=0.006M

Conc of the stock solution C1=0.006M

Initial volume for making the diluted solution(V1)=3ml

final volume of the diluted solution=100ml

from dilution principle

no of mole=conc × volume

initial conc(C1)×initial volume(V1)=final conc(C2)×final volume(V2)

C2=0.006M×3ml/100ml

=0.00018M

4 0
3 years ago
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