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Salsk061 [2.6K]
3 years ago
11

A scientific model is based on assumptions that limit where and how the model can be applied. True False​

Physics
1 answer:
belka [17]3 years ago
6 0

Answer:

i think it is true

Explanation:

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A sharp edged orifice with a 60 mm diameter opening in the vertical side of a large tank discharges under a head of 6 m. If the
Ierofanga [76]

Answer:

The discharge rate is Q = 0.0192 \  m^3 /s

Explanation:

From the question we are told that

   The  diameter is  d =  60 \ mm   =  0.06 \ m

    The  head is  h  =  6 \ m

     The  coefficient of contraction is  Cc  =  0.68

     The  coefficient of  velocity is  Cv  =  0.92

The radius is mathematically evaluated as

         r =  \frac{d}{2}

substituting values

        r =  \frac{ 0.06 }{2}

        r =  0.03 \ m

The  area is mathematically represented as

      A =  \pi r^2

substituting values

      A =  3.142 *  (0.03)^2

      A = 0.00283 \ m^2

 The  discharge rate is mathematically represented as

        Q =  Cv *Cc  *  A  *  \sqrt{ 2 * g *  h}

substituting values

       Q = 0.68 *  0.92*   0.00283  *  \sqrt{ 2 * 9.8 *  6}

       Q = 0.0192 \  m^3 /s

6 0
3 years ago
John goes grocery shopping with his mother. His job is to push the cart. The cart is
lora16 [44]

Answer:

Beacause he has more grocceries and food heavy

Explanation:

7 0
3 years ago
Name two types of sound wave​
kiruha [24]

Explanation:

two types of sound wave

  1. transverse wave
  2. Longitudinal wave
5 0
3 years ago
A marble rolls 269cm across the floor with a constant speed of in 44.1cm/s.
Marrrta [24]

Answer:

t = 6.09 seconds

Explanation:

Given that,

Speed, v = 44.1 cm/s

Distance, d = 269 cm

We need to find the time interval of the marble. Speed is distance per unit time.

v=\dfrac{d}{t}\\\\\implies t=\dfrac{d}{v}\\\\t=\dfrac{269\ \text{cm}}{44.1\ \text{cm/s}}\\\\t=6.09\ s

Hence, the time interval of the marble is 6.09 seconds.

6 0
4 years ago
a slender rod of mass m and length l is released from rest in a horizontal position. what is the rod's angular velocity when it
Makovka662 [10]

Answer:

M g H / 2 = M g L / 2      initial potential energy of rod

I ω^2 / 2 = 1/3 M L^2 * ω^2 / 2   kinetic energy attained by rod

M g L / 2 = 1/3 M L^2 * ω^2 / 2

g = 3 L ω^2

ω = (g / (3 L))^1/2

8 0
2 years ago
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