Answer: 195.3 K
Explanation: Use Charles Law to get T2
Charles Law V1 / T1 = V2 / T2
Derive the equation to find T2
T2 = V2T1 / V1
Convert temperature into K
T1 = 20.0 °C + 273 = 293 K
Substitute the values:
4.00 L x 293 K / 6.00 L = 195. 3 K
7.22 moles of C2H6. Since there are 2 carbon atoms per C2H6, we must multiply the number of moles of C2H6 by 2 to get the number of moles of Carbon which is 14.4 or 14 if using two sig figs.
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Answer: 1709.4 Joules
Explanation:
The quantity of Heat Energy (Q) released on cooling a heated substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)
Thus, Q = MCΦ
Since Q = ?
M = 18.5 grams
Recall that the specific heat capacity of copper C = 0.385 J/g.C
Φ = 285°C - 45°C = 240°C
Then, Q = MCΦ
Q = 18.5grams x 0.385 J/g.C x 240°C
Q = 1709.4 Joules
Thus, 1709.4 Joules is released when copper is cooled.
Answer:
Explanation:
8.61+5.779 = 14.389 = 1.4389 × 10^1
25 - 12.5 = 1.25 x 10^1
56.35 / 13.2 = 4.2689
