Given: ∠A is a straight angle. ∠B is a straight angle.
We need to Prove: ∠A≅∠B.
We know straight angles are of measure 180°.
So, ∠A and <B both would be of 180°.
It is given that ∠A and ∠B are straight angles. This means that <u>both angles are of 180°</u> because of the <u>the definition of straight angles</u>. Using <u>the definition of equality</u>, m∠A=m∠B . Finally, ∠A≅∠B by <u>definition of congruent. </u>
Answer:
x = 10.5
Step-by-step explanation:
we know that ZP = PX (its the midpoint of the rectangle)
11 = PX
ZP + PX = ZX
11+11 = ZX
22 = ZK
2x + 1 = 22
2x = 22 -1
2x = 21
x = 21/2
x = 10.5
Answer:
Not sure of the rest but hope this helps
The area would be 83.67 cm.
A semicircle is half of a circle. The perimeter of the semicircle would be half of the perimeter (circumference) of the entire circle. The formula for circumference is:
C=πd
Using our information, we have
22.92 = 0.5(3.14)d
22.92 = 1.57d
Divide both sides by 1.57:
22.92/1.57 = 1.57d/1.57
14.6≈d
Since the diameter is 14.6, the radius is 14.6/2 = 7.3.
We use the radius for the area of the semicircle:
A=0.5πr²
=0.5(3.14)(7.3)²
=83.67