The formula for phosphorus is P4
Answer:
The volume of hydrogen gas generated by given reaction is 9.48 L
Explanation:
Firstly, we calculate the mole of Zinc added, n = 25.5 / 65 = 0.392 mol
With the same equivalent, the mole of generated hydrogen gas will be the same, at 0.392 mol.
Secondly, we get the equation
<em>P . V = n . R . T</em>
with P (pressure, atm), V (volume, litre), n (mole, mol), R (ideal gas constant, 0.082), T (temperature, Kelvin)
So we have to convert the given information to correct unit
P = 742 mmHg = 0.976 atm
T = 15 °C = 288 K
Hence we can calculate the generated volume by
V = n . R . T / P = 0.392 x 0.082 x 288 / 0.976 = 9.48 L
Answer:
Fe₂O₃ + 3Zn → 2Fe + 3ZnO
Explanation:
Step 1: RxN
Fe₂O₃ + Zn → Fe + ZnO
Step 2: Balance RxN
We need 2 Fe's on both sides.
We also need 3 O's on both sides.
- If we multiply ZnO by 3, we will need 3 Zn's as well
Fe₂O₃ + 3Zn → 2Fe + 3ZnO
Answer:
2Mg + O2 → 2MgO
Explanation:
In all conbustion you should know, that reactans are an specific compound and O2, so the products must be CO2 and H2O, or in this case, the corresponding oxide.
