Answer:
I couldn't find options for your question online, but I can give you an explanation so you can choose the correct option.
Explanation:
A spark knock is a form of unpredictable behavior that occurs in combustion, that is, in the chemical reaction that occurs between oxygen and an oxidizable material. Such combustion is usually manifested by incandescence or flame.
The spark knock is a detonation that occurs when there is a lot of pressure in the fuel.
<u>Some situations in which this can happen are:
</u>
- Engine overloaded.
- Maximum pressure in the cylinders.
- Engine overheated.
- Overheated air.
- Long and excessive engine ignition timing.
- Spark plug at high temperatures.
Answer:
Explanation:
Step by step solved solution is given in the attached document.
Answer:
![250\ \text{lbm/min}](https://tex.z-dn.net/?f=250%5C%20%5Ctext%7Blbm%2Fmin%7D)
![625\ \text{ft/min}](https://tex.z-dn.net/?f=625%5C%20%5Ctext%7Bft%2Fmin%7D)
Explanation:
= Area of section 1 = ![10\ \text{ft}^2](https://tex.z-dn.net/?f=10%5C%20%5Ctext%7Bft%7D%5E2)
= Velocity of water at section 1 = 100 ft/min
= Specific volume at section 1 = ![4\ \text{ft}^3/\text{lbm}](https://tex.z-dn.net/?f=4%5C%20%5Ctext%7Bft%7D%5E3%2F%5Ctext%7Blbm%7D)
= Density of fluid = ![0.2\ \text{lb/ft}^3](https://tex.z-dn.net/?f=0.2%5C%20%5Ctext%7Blb%2Fft%7D%5E3)
= Area of section 2 = ![2\ \text{ft}^2](https://tex.z-dn.net/?f=2%5C%20%5Ctext%7Bft%7D%5E2)
Mass flow rate is given by
![m=\rho A_1V_1=\dfrac{A_1V_1}{v_1}\\\Rightarrow m=\dfrac{10\times 100}{4}\\\Rightarrow m=250\ \text{lbm/min}](https://tex.z-dn.net/?f=m%3D%5Crho%20A_1V_1%3D%5Cdfrac%7BA_1V_1%7D%7Bv_1%7D%5C%5C%5CRightarrow%20m%3D%5Cdfrac%7B10%5Ctimes%20100%7D%7B4%7D%5C%5C%5CRightarrow%20m%3D250%5C%20%5Ctext%7Blbm%2Fmin%7D)
The mass flow rate through the pipe is ![250\ \text{lbm/min}](https://tex.z-dn.net/?f=250%5C%20%5Ctext%7Blbm%2Fmin%7D)
As the mass flowing through the pipe is conserved we know that the mass flow rate at section 2 will be the same as section 1
![m=\rho A_2V_2\\\Rightarrow V_2=\dfrac{m}{\rho A_2}\\\Rightarrow V_2=\dfrac{250}{0.2\times 2}\\\Rightarrow V_2=625\ \text{ft/min}](https://tex.z-dn.net/?f=m%3D%5Crho%20A_2V_2%5C%5C%5CRightarrow%20V_2%3D%5Cdfrac%7Bm%7D%7B%5Crho%20A_2%7D%5C%5C%5CRightarrow%20V_2%3D%5Cdfrac%7B250%7D%7B0.2%5Ctimes%202%7D%5C%5C%5CRightarrow%20V_2%3D625%5C%20%5Ctext%7Bft%2Fmin%7D)
The speed at section 2 is
.
Answer:
Depends on the battery and the current type.
Is it AC or DC?
Explanation:
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