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sattari [20]
3 years ago
9

You have to decide to change the temperature at which you run a certain reaction in hope of obtaining more product more quickly.

You find that you actually get less of the desired product, although you get to the equilibrium state more quickly. Explain what happened.
Chemistry
1 answer:
Alexandra [31]3 years ago
4 0

Answer:

see explanation

Explanation:

The reaction has a negative rate law; i.e., Rate = - ΔConcentration / ΔTime which is graphically a negative slope for the plot of Rate as a function of reactant concentration. => Rate ∝ f(Reactant Concentration). However, by raising the temperature, an increase the probability of reaction occurs and the formation of more product.

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A truck is moving at the rate of 40 km/hr. How far does it move when it stops after 5 seconds?
seraphim [82]
First of all, this is the chemistry section, while your question is a physics question. Anyway I'll tell you how to solve it.

First we need to find the rate that the truck moves in a second.

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40000m/hr ÷ 60 = 666.66(repeating)/minute
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666.66m/min ÷ 60 = 11.11(rep)m/s

Next we simply multiply the speed of the truck by the number of seconds it travels.

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Make sure to round it unless you indicate the repeating decimal.
The truck moved 55.56m in 5 seconds.
6 0
3 years ago
A student measures the volume of a solution to be 0.01370 l. How many significant digits are in this measurement?
Mkey [24]

A student measures the volume of a solution to be 0.01370 have 5 significant digits in this measurement.

<h3>What are significant digits?</h3>

The significant digits are the minimum number from zero to nine for reporting any measurement where the digits are uncertain.

The significant digits starting from zero are not significant digits, decimal is not a significant digit, and ending zero after the decimal are significant digits.

Therefore, the student measures the volume of a solution to be 0.01370 5 significant digits are in this measurement.

Learn more about significant digits, here:

brainly.com/question/1658998

#SPJ4

7 0
2 years ago
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