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sattari [20]
3 years ago
9

You have to decide to change the temperature at which you run a certain reaction in hope of obtaining more product more quickly.

You find that you actually get less of the desired product, although you get to the equilibrium state more quickly. Explain what happened.
Chemistry
1 answer:
Alexandra [31]3 years ago
4 0

Answer:

see explanation

Explanation:

The reaction has a negative rate law; i.e., Rate = - ΔConcentration / ΔTime which is graphically a negative slope for the plot of Rate as a function of reactant concentration. => Rate ∝ f(Reactant Concentration). However, by raising the temperature, an increase the probability of reaction occurs and the formation of more product.

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A molecule of acetone and a molecule of propyl aldehyde are both made from 3 carbon atoms, 6 hydrogen atoms, and 1 oxygen atom.
TEA [102]

Explanation:

The structures of both acetone and propanal are shown below:

In the formula of propanal there is -CHO functional group at the end.

In acetone -CO- group is present in the middle that is on the second carbon.

The molecular formula is C3H6O.

Both have same molecular formula but different structural formulas.

7 0
3 years ago
Help me is a critic acid a solid or a liquid??​
Musya8 [376]

Answer:

See below

Explanation:

It is neither, at least not at room temperature.

Citric acid exists as a power at room temperature, but can be crystallized from cold water. This can be considered it's " solid state, " but as I mentioned before this acid is a powder. Take a look at the attachment below. This is a citric acid present as a crystal;

7 0
3 years ago
At standard pressure, ammonia melts at 195 K and boils at 240 K. If a sample of ammonia at standard pressure is cooled from 200
Svetradugi [14.3K]

Answer:

I) the heat capacity of ammonia(s)

II) the heat capacity of ammonia(ℓ)

IV) the enthalpy of fusion of ammonia

Explanation:

Initially, ammonia at 200 K is liquid. To calculate the change of enthalpy from 200 K to 195 K (melting point) we need to know the heat capacity of ammonia(ℓ).

At 195, ammonia is in the transition from liquid to solid (solidification). To calculate the change of enthalpy in that process we need to know the enthalpy of solidification of ammonia, which has the same value but opposite sign to the enthalpy of fusion of ammonia.

From 195 K to 0 K, ammonia is solid. To calculate the change of enthalpy in that process we need to know the heat capacity of ammonia(s).

7 0
3 years ago
QUESTION 3
ddd [48]

Answer:

Different visible waves show different colors

5 0
3 years ago
How many significant figures are in 340500
vovikov84 [41]
There are 4 significant digits: 3405.
4 0
3 years ago
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