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Nataliya [291]
3 years ago
15

A Ferris wheel is a vertical, circular amusement ride with radius 6.0 m. Riders sit on seats that swivel to remain horizontal. T

he Ferris wheel rotates at a constant rate, going around once in 9.6 s. Consider a rider whose mass is 96 kg.
Physics
1 answer:
Oksana_A [137]3 years ago
8 0

Answer:

Incomplete question

The complete question is

A Ferris wheel is a vertical, circular amusement ride with radius 6.0 m. Riders sit on seats that swivel to remain horizontal. The Ferris wheel rotates at a constant rate, going around once in 9.6 s. Consider a rider whose mass is 96 kg.

At the bottom of the ride, what is the rate of change of the rider's momentum?

Explanation:

Radius of wheel is 6m

Rider mass=96kg

He completes one revolution in 9.6s

Let get angular velocity (w)

1 Revolution =2πrad

θ=2πrad

w= θ/t

w=2π/9.6

w=0.654rad/s

Linear speed is give as

v=wr

v=0.654×6

v=3.93m/s

Centripetal acceleration a

a=rw²

a=6×0.654²

a=2.57m/s²

Acceleration due to gravity g=9.81m/s²

According to Newton's second law of motion net force acting on the rider at the bottom of the ride is given by: the two force acting at the bottom is the normal and the weight of the rider

ΣF = ma

N-W=ma

N-mg=ma

N=ma+mg

N=m(a+g)

N=96(2.57+9.81)

N=1188.48 N

Therefore the rate of change of momentum at the bottom of the ride is 1188.48 N.

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The circumference of the earth is 40,000 km. The distance from the
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Answer:

The distance from the North Pole to the equator is 1*10^{7}m.

Explanation:

Circumference of Earth = 40,000 km    ......................(1)

Distance from the North Pole to the Equator is =  1/4th of the Circumference of Earth  ......................  (2)

Let Distance from the North Pole to the Equator be  d ,

the equation formed will be ,

d = 1/4 * Circumference of Earth       ........(3)......... ( from equation 1 )

put the value of Circumference of Earth in equation (3),

d = 1/4 * 40,000  km

d = 10,000 km

converting km to m ,

d = 10,000 * 10^{3} m

d =  1 * 10^{7} m

The distance from the North Pole to the equator is 1*10^{7}m.

7 0
3 years ago
A mass on the end of a spring undergoes simple harmonic motion. At the instant when the mass is at its maximum displacement from
Mrac [35]

Answer:

C) True. At maximum displacement, its instantaneous velocity is zero.

Explanation:

The simple harmonic movement is given by

        x = A cos wt

Speed

        v = - A w sin wt

At the point of maximum displacement x = A

       A = A cos wt

      cos wt = 1

      wt = 0

We replace the speed

       v = -Aw sin 0 = A w

Speed ​​is maximum

Let's review the claims

A) False. Speed ​​is zero

B) False. It can be determined

C) True. Agree with our result

D) False. When one is maximum the other is minimum

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2 years ago
What type of force pulls in two opposite directions?
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Magnets facing the same way  <span />
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An object with a mass of 10 kg is accelerated upward at 2 m/sec2. What force is required?
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Answer:

Answer: Given m = 10 kg and . F = 20 N. Thus, the force required to accelerate the object upward direction is 20 N.

Explanation:

Answer: Given m = 10 kg and . F = 20 N. Thus, the force required to accelerate the object upward direction is 20 N.

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2 years ago
An x-ray beam of wavelength 1.4×10−10m makes an angle of 20° with a set of planes in a crystal(the Bragg angle)causing first ord
Gnom [1K]

Answer:

Second order line appears at 43.33° Bragg angle.

Explanation:

When there is a scattering of x- rays from the crystal lattice and interference occurs, this is known as Bragg's law.

The Bragg's diffraction equation is :

n\lambda=2d\sin\theta      .....(1)

Here n is order of constructive interference, λ is wavelength of x-ray beam, d is the inter spacing distance of lattice and θ is the Bragg's angle or scattering angle.

Given :

Wavelength, λ = 1.4 x 10⁻¹⁰ m

Bragg's angle, θ = 20°

Order of constructive interference, n =1

Substitute these value in equation (1).

1\times1.4\times10^{-10} =2d\sin20

d = 2.04 x 10⁻¹⁰ m

For second order constructive interference, let the Bragg's angle be θ₁.

Substitute 2 for n, 2.04 x 10⁻¹⁰ m for d and 1.4 x 10⁻¹⁰ m for λ in equation (1).

2\times1.4\times10^{-10} =2\times2.04\times10^{-10} \sin\theta_{1}

\sin\theta_{1} =0.68

<em>θ₁ </em>= 43.33°

4 0
2 years ago
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