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brilliants [131]
3 years ago
14

1 point

Chemistry
1 answer:
masya89 [10]3 years ago
8 0

Answer:

V_2=1.34L

Explanation:

Hello there!

In this case, since this problem is describing how pressure changes as a function of volume and vice versa, it is possible recall the Boyle's law as shown below:

P_1V_1=P_2V_2

Whereas we are asked to compute the volume when the change is pressure is performed (V₂); thus, we proceed as follows:

V_2=\frac{P_1V_1}{P_2}\\\\V_2=\frac{1.55L*105.2kPa}{122.0kPa}\\\\V_2=1.34L

Best regards!

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