Question

A roller coaster accelerates from an initial speed of 6.0 m/s to a final of 70 m/s over 4 seconds. What is the rigth formula to solve the problem? Acceleration formulas: 1) v2=v1+ at 2)d=1/2(v2-v1)t 3)d=v1t + 1/2 at2 4) d=v2t - 1/2 at2 5) v2=v1+2ad a 1 b 2 c 3 d 4 e 5

Answer 1

Answer:

a = 16 m/s²

Explanation:

Given that,

Initial speed of a roler coaster, v₁ = 6 m/s

Final speed of a roller coaster, v₂ = 70 m/s

Time, t = 4s

We know that, acceleration of an object is equal to the rate of change of velocity. Let the acceleration be a. Its formula is given by :

$a=\dfrac{v_2-v_1}{t}$

or

$v_2=v_1+at$

The correct option is (1). Its value is equal to :

$a=\dfrac{70-6}{4}\\\\a=16\ m/s^2$

Its value is equal to 16 m/s².