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3 years ago

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A roller coaster accelerates from an initial speed of 6.0 m/s to a final of 70 m/s over 4 seconds. What is the rigth formula to

solve the problem? Acceleration formulas: 1) v2=v1+ at 2)d=1/2(v2-v1)t 3)d=v1t + 1/2 at2 4) d=v2t - 1/2 at2 5) v2=v1+2ad a 1 b 2 c 3 d 4 e 5

1 answer:

Anton [14]3 years ago

6 0

Answer:

a = 16 m/s²

Explanation:

Given that,

Initial speed of a roler coaster, v₁ = 6 m/s

Final speed of a roller coaster, v₂ = 70 m/s

Time, t = 4s

We know that, acceleration of an object is equal to the rate of change of velocity. Let the acceleration be a. Its formula is given by :

$a=\dfrac{v_2-v_1}{t}$

or

$v_2=v_1+at$

The correct option is (1). Its value is equal to :

$a=\dfrac{70-6}{4}\\\\a=16\ m/s^2$

Its value is equal to 16 m/s².

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Joaquin mows the lawn at his grandmother’s home during the summer months. Joaquin measured the

nordsb [41]

Velocity is define as how fast an object is moving, and in what direction, it is a vector quantity, meaning velocity has both magnitude and direction. Anything goes to the left is negative, and anything goes to the right is positive.

a. Direction from east to west, given distance 11.5 meters, and time of 7.10 s

V = displacement/time V = -11.5/7.10 S V = -1.62 m/s (going left)

b. Joaquin reaches his original position. Displacement is now zero.

Velocity of the lawnmower is equal to "zero" but if we calculate for the average speed of the lawn, you just have to add the distance covered and the time it take to go back at the original position or point of origin

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3 years ago

An aluminum bar 600mm long, with diameter 40mm, has a hole drilled in the center of the bar. The hole is 40mm in diameter and 10

s2008m [1.1K]

Answer:

<em>1.228 x </em> $10^{-6}$ <em> mm </em>

<em></em>

Explanation:

diameter of aluminium bar D = 40 mm

diameter of hole d = 30 mm

compressive Load F = 180 kN = 180 x $10^{3}$ N

modulus of elasticity E = 85 GN/m^2 = 85 x $10^{9}$ Pa

length of bar L = 600 mm

length of hole = 100 mm

true length of bar = 600 - 100 = 500 mm

area of the bar A = $\frac{\pi D^{2} }{4}$ = $\frac{3.142* 40^{2} }{4}$ = 1256.8 mm^2

area of hole a = $\frac{\pi(D^{2} - d^{2}) }{4}$ = $\frac{3.142*(40^{2} - 30^{2})}{4}$ = 549.85 mm^2

Total contraction of the bar = $\frac{F*L}{AE} + \frac{Fl}{aE}$

total contraction = $\frac{F}{E} * (\frac{L}{A} +\frac{l}{a})$

==> $\frac{180*10^{3}}{85*10^{9}} *( \frac{500}{1256.8} + \frac{100}{549.85})$ = <em>1.228 x </em> $10^{-6}$ <em> mm </em>

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3 years ago

What is a landform created by plate motion?

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Answer: Volcanoes and ridges are landforms that are created by the movement of tectonic plates.

Explanation:

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3 years ago

Read 2 more answers

you decide to work part time at a local supermarket. The job pays eight dollars and 60 per hour and you work 20 hours per week.

aleksley [76]

Answer:

I guess that we want to find how much money you get each week.

We know that the job pays $8.60 per hour.

We know that you work 20 hours per week.

Then the gross pay (the total money that you earn) in a week is 20 times $8.60, or:

20*$8.60 = $172.

Now we know that your employer witholds:

10% + 7.65% + 5% = 22.65%

Then your employer withholds 22.65% of your gross pay.

if the 100% of your gross pay is $172

Then the 22.65% will be:

(22.65%/100%)*$172 = 0.2265*$172 = $38.96

This means that your employer withholds $38.96 of your weekly gross pay.

Then each week you get:

$172 - $38.96 = $133.04

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3 years ago

Three students have been studying relative motion and decide to do an experiment to demonstrate their knowledge. The experiment

miskamm [114]

Answer with Explanation:

We are given that

Constant speed of Jane=12.6 m/s

a.When Fred can throw the ball 30 m/s

We have to find the angle relative to the horizontal when he throw the ball in order for Sue to see the ball travel vertically upward.

Let $\theta$ be the angle .

Therefore,

$30 cos\theta=12.6$

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$\theta=cos^{-1}(0.42)=65.165^{\circ}$

b.We have to find the height to which ball reach.

$v^2-v^2_0=2aS$

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