A roller coaster accelerates from an initial speed of 6.0 m/s to a final of 70 m/s over 4 seconds. What is the rigth formula to
1 answer:
Answer:
a = 16 m/s²
Explanation:
Given that,
Initial speed of a roler coaster, v₁ = 6 m/s
Final speed of a roller coaster, v₂ = 70 m/s
Time, t = 4s
We know that, acceleration of an object is equal to the rate of change of velocity. Let the acceleration be a. Its formula is given by :
or
The correct option is (1). Its value is equal to :
Its value is equal to 16 m/s².
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Answer:
a) 2.7s
b) 29 m/s
Explanation:
The equation for the velocity and position of a free fall are the following
-(1)
- (2)
Since the hot-air ballon is <em>descending </em>at 2.1m/s and the camera is dropped at 42 m above the ground:
To calculate the time which it takes to reach the ground we use eq(2) with x=0, and look for the positive solution of t:
t = 2.71996
Rounding to two significant figures:
t = 2.7 s
Now we calculate the velocity the camera had just before it lands using eq(1) with t=2.7s
v = -28.782 m/s
Rounding to two significant figures:
v = -29 m/s
where the minus sign indicates the downwards direction
Answer:
Time, t = 8 seconds
Explanation:
An object is thrown upward from the top of a 128-foot building with an initial velocity of 112 feet per second. The height h as a function of time t is given by :
We need to find the time when the object will hit the ground. When it will hit the ground, h = 0
So,
On solving the above quadratic equation, we get the value of t = 8 seconds. So, after 8 seconds the object will hit the ground. Hence, this is the required solution.