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3 years ago

What is the formula to calculate the readings on an ammeter?

2 answers:

8 0

An ammeter works like a galvanometer except for the existence of a resistance that is attached in parallel. The pointer will have torque on it because of the coil. The equation is expressed as:
<span>
S = G/n-1 </span>
where G is the main resistance and S is the shunt resistance while n is a range ratio.

Cloud [144]3 years ago

4 0

If the voltage and the resistance are known within the circuit, then you can use the formula:

Current = Voltage / Resistance

If you know the amount of charge going past a certain location in a certain amount of time, then you can find the current using:

Current = charge / time

You might be interested in

Whose contributions to astronomy explained how planets were held in their orbits?

ankoles [38]

Answer:

D newton

Explanation:

he did extensive research on gravity, and gravity is what holds planets in orbits.

3 0

3 years ago

Check and double-click on the red polygon for the Henry Mountains laccolith complex in the folder labeled Problem 1. This comple

MArishka [77]

Answer: ghg

Explanation:

4 0

3 years ago

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The length of a rectangle is increasing at a rate of 4 cm/s and its width is increasing at a rate of 6 cm/s. When the length is

Fudgin [204]

Answer:

24cm/s

Explanation:

A=L*w

A'=L'*w'

L=13

w=5

L'=4

w'=6

A=?

A'=?

A=L*w

A=13*5

A=65

A'=L'*w'

A'=4*6

A'=24

*the given lengths are just to throw you off*

3 0

3 years ago

The energy of an object can be converted to heat due to the friction of the car on the hill. The difference between the potentia

MAVERICK [17]

Answer:

Energy Lost for group A's car = 0.687 J

Energy Lost for group B's car = 0.55 J

Explanation:

The exact question is as follows :

Given - The energy of an object can be converted to heat due to the friction of the car on the hill. The difference between the potential energy of the car and its kinetic energy at the bottom of the hill equals the energy lost due to friction.

To find - How much energy is lost due to heat for group A's car ?

How much for Group B's car ?

Solution -

We know that,

GPE = 1 Joule (Potential Energy)

Now,

For Group A -

Energy Lost = GPE - KE

= 1 J - 0.313 J

= 0.687 J

So,

Energy Lost for group A's car = 0.687 J

Now,

For Group B -

Energy Lost = GPE - KE

= 1 J - 0.45 J

= 0.55 J

So,

Energy Lost for group B's car = 0.55 J

8 0

3 years ago

The force diagram represents a girl pulling a sled with a mass of 6.0 kg to the left with a force of 10.0 N at a 30.0 degree ang

Vilka [71]

Normal Force = 54 N
acceleration = 1.2 m/s^2

For Normal Force:
According to the force diagram, we can come up with the equation (all up and down forces):

10 sin 30 + Normal Force - 58.8 = 0
Normal Force = 53.8 N = 54 N

For acceleration:
According to the force diagram, we can come up with the equation (all left and right forces):

10 cos 30 - 1.5 = (6.0) (Acceleration)
Acceleration = 1.19 m/s^2 = 1.2 m/s^2

3 0

3 years ago

Read 2 more answers