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blsea [12.9K]
3 years ago
11

How does the density and distribution of your “stars” change as the balloon expands?

Chemistry
1 answer:
Anna35 [415]3 years ago
3 0

Answer:

The Universe is constantly expanding and as it expands the stars and objects in space move farther apart, just like the points on the balloon when air is blown into it. Density and distribution of "stars" as the balloon expands because when volume increases the density will increase.

Hope this Helps

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Teeth and long bones are good indicators of age in children; ribs and joints are better for adults.
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Answer:

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Explanation:

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What is the molarity of an aqueous solution that contains 78g of C6H12O6 dissolved in 2500 mL of solution?
dusya [7]

Answer:

\boxed {\boxed {\sf molarity = 0.17 \ M \ C_6H_12O_6}}

Explanation:

Molarity is found by dividing the moles of solute by liters of solution.

molarity = \frac {moles}{liters}

We are given grams of a compound and milliliters of solution, so we must make 2 conversions.

1. Gram to Moles

We must use the molar mass. First, use the Periodic Table to find the molar masses of the individual elements.

  • C: 12.011 g/mol
  • H: 1.008 g/mol
  • O: 15.999 g/mol

Next, look at the formula and note the subscripts. This tells us the number of atoms in 1 molecule. We multiply the molar mass of each element by its subscript.

6(12.011)+12(1.008)+6(15.999)=180.156 g/mol

Use this number as a ratio.

\frac {180.156 \ g\ C_6H_12 O_6}{ 1 \ mol \ C_6H_12O_6}

Multiply by the given number of grams.

78 \ g \ C_6H_12O_6 *\frac {180.156 \ g\ C_6H_12 O_6}{ 1 \ mol \ C_6H_12O_6}

Flip the fraction and divide.

78 \ g \ C_6H_12O_6 *\frac { 1 \ mol \ C_6H_12O_6}{180.156 \ g\ C_6H_12 O_6}

\frac { 78 \ mol \ C_6H_12O_6}{180.156 }= 0.432958102977 \ mol \ C_6H_12O_6

2. Milliliters to Liters

There are 1000 milliliters in 1 liter.

\frac {1 \ L }{ 1000 \ mL}

Multiply by 2500 mL.

2500 \ mL* \frac {1 \ L }{ 1000 \ mL}

2500 * \frac {1 \ L }{ 1000 }= 2.5 \ L

3. Calculate Molarity

Finally, divide the moles by the liters.

molarity = \frac {0.432958102977 \ mol \ C_6H_12O_6}{ 2.5 \ L}

molarity = 0.173183241191 \ mol \ C_6H_12O_6/L

The original measurement has 2 significant figures, so our answer must have the same. That is the hundredth place and the 3 tells us to leave the 7.

molarity \approx 0.17 \ mol \ C_6H_12O_6 /L

1 mole per liter is also equal to 1 M.

molarity = 0.17 \ M \ C_6H_12O_6

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